## anonymous 4 years ago dx/dt of ln((t^2)+3)

1. myininaya

$(\ln(t^2+3))'=\frac{(t^2+3)'}{t^2+3}$

2. anonymous

how about if we dash it again? what would the answer be?

3. anonymous

use product rule.

4. anonymous

eerrrr quotient rule i mean

5. myininaya

you mean chain rule

6. anonymous

could you show me how to do that please?

7. myininaya

i showed you above all you need to do is find the derivative of t^2 and derivative of 3 $\frac{(t^2+3)'}{t^2+3}=\frac{2t+0}{t^2+3}$

8. anonymous

oh no what i mean is if we had to dash it again , like second derivative

9. myininaya

dash it again? so you want to find $(\frac{2t}{t^2+3})'?$

10. myininaya

you will use quotient rule

11. anonymous

yes

12. anonymous

derivative ln(t2+3) 1/(t^2+3)*(2t)Dt

13. anonymous

dash again

14. anonymous

|dw:1326853065865:dw|

15. anonymous

i want to find second derivative

16. myininaya

shiign just put 2nd derivative

17. myininaya

all he did was use quotient rule

18. anonymous

so the answer is -2t^2 +6 /(t^2+3)^2

19. anonymous

is that correct or not?

20. anonymous

yes