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anonymous
 5 years ago
Determine whether the series converges or diverges. (Answer: converges)
sum from n=1 to infinity of (n^2 + 2^n)/(n + 3^n)
anonymous
 5 years ago
Determine whether the series converges or diverges. (Answer: converges) sum from n=1 to infinity of (n^2 + 2^n)/(n + 3^n)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=1}^{\infty}(n^2 + 2^n)/(n + 3^n)\]

mathmate
 5 years ago
Best ResponseYou've already chosen the best response.0Divide top and bottom by n^2 (1+2^n/n^2)/(1/n+3^n/n^2) as n>inf, 1 and 1/n drop off: (2/3)^n Use ratio test as n> inf a(n+1)/a(n) =(2/3)=2/3 < 1 so the series converges.
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