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anonymous

  • 5 years ago

Solving Square Root Equations 5(squareroot of)x-1=(squaredrootof) x+1

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  1. dumbcow
    • 5 years ago
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    square both sides --> 25(x-1) = x+1

  2. anonymous
    • 5 years ago
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    yes, but i need to get x. :(

  3. dumbcow
    • 5 years ago
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    you can solve it from there get x by itself

  4. anonymous
    • 5 years ago
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    it would be 25x? thats somethign i dont get.

  5. anonymous
    • 5 years ago
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    \[5\sqrt{x-1}=\sqrt{x+1}\]\[(5\sqrt{x-1})^{2}=(\sqrt{x+1})^2\]\[25(x-1)=x+1\]\[25x-25=x+1\]-x +25 -x +25\[24x=26\]/24 /24\[x=\]

  6. anonymous
    • 5 years ago
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    i dont get the 5th step...

  7. anonymous
    • 5 years ago
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    The "-x +25 -x +25" step?

  8. anonymous
    • 5 years ago
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    wouldnt it be 24x-24=0? yeah yhat step.

  9. anonymous
    • 5 years ago
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    No\[-25-1=-26\]

  10. anonymous
    • 5 years ago
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    wooow... feeling like a genius...

  11. anonymous
    • 5 years ago
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    If you moved both the x and 1 from the right side to the left you'd subtract -1 from a negative 25, making you go more negative.

  12. anonymous
    • 5 years ago
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    I hate making those simple mistakes.

  13. anonymous
    • 5 years ago
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    okay. so, if i also take the x out, because i want to have =0, it owuld be 24x-26=o, correct?

  14. anonymous
    • 5 years ago
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    Yes.

  15. anonymous
    • 5 years ago
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    so now i factor it, right?

  16. anonymous
    • 5 years ago
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    You shouldn't need to factor it.\[24x-26=0\]Should be the equation. Move -26 over to get\[24x=26\]Then divide to get the answer.

  17. anonymous
    • 5 years ago
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    :) whoops. Thanks.

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