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which part is under the sqrt?
x = -10, -1
dang it you beat me!
But -10 does not check so discard it.
what do you mean by "not checking"
so the only answer is -1
If you put it back in the original equation, it does not make a true sentence.
ahhh... so i know on the2nd to 3rd step you skipped the math involved.. i get -3x=x^2+8x+10 am i correct?
well, would you count it or not because you could do -6,6 = -10+4, one of those is true
oh i see.
Yes Luci, you are correct
so you divide it all by -3... right? to get x alone?
but sqrt(36) also = 6, and -10 + 4 is -6, so - 6 = -6 but 6 ~= -6
only use principle square root in this case?
whoops nevermind... blonde moment. ://
hey, i am blonde, watch it
Luci, subtract 3x from both sides.
mridrik, did you look at the drawing I made? The square root symbol means the POSITIVE root
Mertsj... yeah, lol i barely saw that :/ and mridrik.. im blonde too so it's okay:)
But why wouldnt you also accept the - root? -6^2 is also 36
yeah only blondes can make fun of blondes
Is that not the original problem? Do you see anything there about the negative root?
the original problem says sqrt(-3x+6) = x + 4, if x is negative ten, then sqrt(36) = x + 4, the square root of 36 is positive and negative 6, I'm just wondering why you dont use the negative six, I understand some problems just mean the principle square root, but how do i know when it means that?
that's a good question... i don't know?
The answer is no
Here is the original problem
It does NOT say this:
Therefore it is ONLY the POSITIVE root