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anonymous

  • 5 years ago

(squaredrootof)x-5=(squaredrootof)x-1 [the -1 is not inside the squaredroot) :)

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  1. dumbcow
    • 5 years ago
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    square both sides you have to FOIL the right side

  2. anonymous
    • 5 years ago
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    uhhh.... i need help with that :///

  3. anonymous
    • 5 years ago
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    \[\sqrt{x-5}=\sqrt{x}-1\]\[(\sqrt{x-5})^2=(\sqrt{x}-1)^2\]v-------------^\[(\sqrt{x}-1)(\sqrt{x}-1)\]FOIL \[(x-\sqrt{x}-\sqrt{x}+1)\]\[(x-2\sqrt{x}-1)\]\[x-5=x-2\sqrt{x}+1\]-x -1 -x -1 \[-6=-2\sqrt{x}\]/-2 /-2\[3=\sqrt{x}\]\[(3)^2=(\sqrt{x})^2\]\[9=x\]Finished!!!

  4. anonymous
    • 5 years ago
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    woah.. id nt get the foil.. why woudl (sqrdrt) of x multiplied by the same thing give x?

  5. anonymous
    • 5 years ago
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    I forget the name of the actual rule. But simply it's\[(x^2)(x^3)=x^5\]What you do is take the exponents and add them together.\[\sqrt{x}=x ^{1/2}\]Therefore\[(\sqrt{x})(\sqrt{x})=(x ^{1/2})(x ^{1/2})\]Which then makes\[(x ^{1/2})(x ^{1/2})=x^1\]or x.

  6. anonymous
    • 5 years ago
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    oh. haha. sorry :) and i don't get the x-1-x-1 part.. :(

  7. anonymous
    • 5 years ago
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    \[(x ^{a})(x ^{b})=x ^{a+b}\] That's the rule.

  8. anonymous
    • 5 years ago
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    I'm subtracting x and 1 from each side.

  9. anonymous
    • 5 years ago
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    ooohh... i see it now:) can you repeart that last part? after the little isue i just did? my computer won't show anything after that. :(

  10. anonymous
    • 5 years ago
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    after the -x-1-x-1?

  11. anonymous
    • 5 years ago
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    yes.

  12. anonymous
    • 5 years ago
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    \[x-5=x-2\sqrt{x}+1\]-x -1 -x -1\[-6=-2\sqrt{x}\]/-2 /-2\[3=\sqrt{x}\]\[(3)^2=(\sqrt{x})^2\]\[9=x\]

  13. anonymous
    • 5 years ago
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    what do the /-2/-2 stand for?

  14. anonymous
    • 5 years ago
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    Divide by -2 on both sides.

  15. anonymous
    • 5 years ago
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    okay. :)

  16. anonymous
    • 5 years ago
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    I was taught "The Granny Rule: Granny's are fair, what they do to one chile they do to the other." Same with algebra, what you do to one side of the equation you have to do to the other.

  17. anonymous
    • 5 years ago
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    *child*

  18. anonymous
    • 5 years ago
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    mahaha:) that's a good way to remember it:D

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