(squaredrootof)x-5=(squaredrootof)x-1 [the -1 is not inside the squaredroot) :)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

(squaredrootof)x-5=(squaredrootof)x-1 [the -1 is not inside the squaredroot) :)

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

square both sides you have to FOIL the right side
uhhh.... i need help with that :///
\[\sqrt{x-5}=\sqrt{x}-1\]\[(\sqrt{x-5})^2=(\sqrt{x}-1)^2\]v-------------^\[(\sqrt{x}-1)(\sqrt{x}-1)\]FOIL \[(x-\sqrt{x}-\sqrt{x}+1)\]\[(x-2\sqrt{x}-1)\]\[x-5=x-2\sqrt{x}+1\]-x -1 -x -1 \[-6=-2\sqrt{x}\]/-2 /-2\[3=\sqrt{x}\]\[(3)^2=(\sqrt{x})^2\]\[9=x\]Finished!!!

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

woah.. id nt get the foil.. why woudl (sqrdrt) of x multiplied by the same thing give x?
I forget the name of the actual rule. But simply it's\[(x^2)(x^3)=x^5\]What you do is take the exponents and add them together.\[\sqrt{x}=x ^{1/2}\]Therefore\[(\sqrt{x})(\sqrt{x})=(x ^{1/2})(x ^{1/2})\]Which then makes\[(x ^{1/2})(x ^{1/2})=x^1\]or x.
oh. haha. sorry :) and i don't get the x-1-x-1 part.. :(
\[(x ^{a})(x ^{b})=x ^{a+b}\] That's the rule.
I'm subtracting x and 1 from each side.
ooohh... i see it now:) can you repeart that last part? after the little isue i just did? my computer won't show anything after that. :(
after the -x-1-x-1?
yes.
\[x-5=x-2\sqrt{x}+1\]-x -1 -x -1\[-6=-2\sqrt{x}\]/-2 /-2\[3=\sqrt{x}\]\[(3)^2=(\sqrt{x})^2\]\[9=x\]
what do the /-2/-2 stand for?
Divide by -2 on both sides.
okay. :)
I was taught "The Granny Rule: Granny's are fair, what they do to one chile they do to the other." Same with algebra, what you do to one side of the equation you have to do to the other.
*child*
mahaha:) that's a good way to remember it:D

Not the answer you are looking for?

Search for more explanations.

Ask your own question