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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Where ??
|dw:1326860446078:dw|
the graph shows the velocity of a particle in cm/second. Find the distance traveled by the particle in the first 4 seconds

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If it is a velocity time graph find area under the curve
isn't there a simpler way?
where you just add the distances?
The way you are talking about is using equations of motion now that you are given velocity time graph this is the simplest d=27.5cm
yes that is correct could you show me how you got it thx
Look at the figure again|dw:1326774715723:dw| you shall use area formula for trapezium and square
AWWWW I SEEE THANK YOU!
@ notsobright could you please explain to me why finding the area under the curve equates to finding the distance travelled?

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