anonymous
  • anonymous
243^2/5
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
9 as it is (243^1/5)^2
anonymous
  • anonymous
yeah i figured it out
anonymous
  • anonymous
thanks

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
\[243^{2/5}=\sqrt[5]{243^2}\]\[\sqrt[5]{243^2}=\sqrt[5]{59049}\]\[\sqrt[5]{59049}=9\]
anonymous
  • anonymous
|dw:1326864018846:dw|
anonymous
  • anonymous
\[\sqrt[4]{x ^{16}y^4}=x^4y\]Take out 1 variable for every factor of 4.
anonymous
  • anonymous
oh ok thanks
anonymous
  • anonymous
|dw:1326864378417:dw|
anonymous
  • anonymous
what about this type
anonymous
  • anonymous
Is that\[(x ^{1/2}y^3)^2\sqrt{x^2}\]?
anonymous
  • anonymous
yes that is. sorry bad drawing
anonymous
  • anonymous
It's cool.
anonymous
  • anonymous
We can split that up into two parts\[(x ^{1/2}y^3)^2\]And\[\sqrt{x^2}\]We'll do the first part, there's a rule\[(x^a)^b=x ^{a \times b}\]So...\[(x ^{1/2}y^3)^2=xy^6\]Also, when you have a square being square rooted they cancel out.\[\sqrt{x^2}=x\]Finally\[xy^6x=x^2y^6\]
anonymous
  • anonymous
ok thanks
anonymous
  • anonymous
|dw:1326865345268:dw| so fill in the blank
anonymous
  • anonymous
\[256^{a/4}=4\]\[\sqrt[4]{256^a}=4\]\[(\sqrt[4]{256^a})^4=(4)^4\]\[256^a=256\]\[a=1\]
anonymous
  • anonymous
|dw:1326865703133:dw| so for this what would be the steps
anonymous
  • anonymous
\[243{}^{\wedge}(2/5) = 9 \]\[243{}^{\wedge}2/5 = \frac{59049}{5} \]
anonymous
  • anonymous
\[225^{1/a}=15\]\[\sqrt[a]{225^1}=15\]Any number/variable to the 1 power is that number/variable.\[x^1=x\]\[387461873654^1=387461873654\]\[\sqrt[a]{225}=15\]\[(\sqrt[a]{225})^a=(15)^a\]\[225=15^a\]\[15 \times 15=225\]Therefore\[a=2\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.