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anonymous
 4 years ago
how would i solve 4b8b=10b3b? 3b8=7b. 3b=15b?
anonymous
 4 years ago
how would i solve 4b8b=10b3b? 3b8=7b. 3b=15b?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[4b8b=10b3b\]\[3b8=7b\]3b 3\[8=4b\]/4 /4\[2=b\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You wouldn't go from 3b8=7b > 3b=15b. It would be 3b  8 = 7b 3b 3b 8 = 4b Then divide. /4 /4 b = 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh ok i see what you mean thanks guys

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if i had a problem with fractions how would that work out? would i add to make one side a whole number

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can you give us the problem?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There is no need to mess with fractions in this problem.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is for a different problem.  3/8y=1/16. do i just eliminate one side?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[3/8y=1/16\]\[(8y)(16)(3/8y)=(1/16)(8y)(16)\]\[(16)(3)=(1)(8y)\]\[48=8y\]/8 /8\[6=y\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i can see how you solved it but i dont understand the second line quite well. how 8y and 16 play in that part

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Use "The Granny Rule: Grannies are fair, what they give to one child they give to the other." Same in algebra, what you do to one side of the equation you do to the other. I multiplied both sides by 16 and 8y. On the left side the 8y's canceled out, on the right the 16's canceled out.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh ok i got it, i think thanks
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