anonymous
  • anonymous
how would i solve 4b-8-b=10b-3b? 3b-8=7b. 3b=15b?
Mathematics
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anonymous
  • anonymous
how would i solve 4b-8-b=10b-3b? 3b-8=7b. 3b=15b?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
\[4b-8-b=10b-3b\]\[3b-8=7b\]-3b -3\[-8=4b\]/4 /4\[-2=b\]
anonymous
  • anonymous
You wouldn't go from 3b-8=7b --> 3b=15b. It would be 3b - 8 = 7b -3b -3b -8 = 4b Then divide. /4 /4 b = -2
anonymous
  • anonymous
oh ok i see what you mean thanks guys

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anonymous
  • anonymous
if i had a problem with fractions how would that work out? would i add to make one side a whole number
anonymous
  • anonymous
Can you give us the problem?
anonymous
  • anonymous
There is no need to mess with fractions in this problem.
anonymous
  • anonymous
this is for a different problem. - 3/8y=-1/16. do i just eliminate one side?
anonymous
  • anonymous
Cross multiply
anonymous
  • anonymous
\[-3/8y=-1/16\]\[(8y)(16)(-3/8y)=(-1/16)(8y)(16)\]\[(16)(-3)=(-1)(8y)\]\[-48=-8y\]/-8 /-8\[6=y\]
anonymous
  • anonymous
i can see how you solved it but i dont understand the second line quite well. how 8y and 16 play in that part
anonymous
  • anonymous
Use "The Granny Rule: Grannies are fair, what they give to one child they give to the other." Same in algebra, what you do to one side of the equation you do to the other. I multiplied both sides by 16 and 8y. On the left side the 8y's canceled out, on the right the 16's canceled out.
anonymous
  • anonymous
oh ok i got it, i think thanks

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