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anonymous

  • 5 years ago

how would i solve 4b-8-b=10b-3b? 3b-8=7b. 3b=15b?

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  1. anonymous
    • 5 years ago
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    \[4b-8-b=10b-3b\]\[3b-8=7b\]-3b -3\[-8=4b\]/4 /4\[-2=b\]

  2. anonymous
    • 5 years ago
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    You wouldn't go from 3b-8=7b --> 3b=15b. It would be 3b - 8 = 7b -3b -3b -8 = 4b Then divide. /4 /4 b = -2

  3. anonymous
    • 5 years ago
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    oh ok i see what you mean thanks guys

  4. anonymous
    • 5 years ago
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    if i had a problem with fractions how would that work out? would i add to make one side a whole number

  5. anonymous
    • 5 years ago
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    Can you give us the problem?

  6. anonymous
    • 5 years ago
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    There is no need to mess with fractions in this problem.

  7. anonymous
    • 5 years ago
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    this is for a different problem. - 3/8y=-1/16. do i just eliminate one side?

  8. anonymous
    • 5 years ago
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    Cross multiply

  9. anonymous
    • 5 years ago
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    \[-3/8y=-1/16\]\[(8y)(16)(-3/8y)=(-1/16)(8y)(16)\]\[(16)(-3)=(-1)(8y)\]\[-48=-8y\]/-8 /-8\[6=y\]

  10. anonymous
    • 5 years ago
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    i can see how you solved it but i dont understand the second line quite well. how 8y and 16 play in that part

  11. anonymous
    • 5 years ago
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    Use "The Granny Rule: Grannies are fair, what they give to one child they give to the other." Same in algebra, what you do to one side of the equation you do to the other. I multiplied both sides by 16 and 8y. On the left side the 8y's canceled out, on the right the 16's canceled out.

  12. anonymous
    • 5 years ago
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    oh ok i got it, i think thanks

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