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anonymous
 5 years ago
find f^1(x) for
a) y= 3x2/x+4
b) f(x)= (sqaureroot) x1
anonymous
 5 years ago
find f^1(x) for a) y= 3x2/x+4 b) f(x)= (sqaureroot) x1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How is the first equation set up?\[y=(3x2)/(x+4)\]or\[y=3x(2/x)+4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1326869840414:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[f ^{1}(x)=f(y)\]\[x=(3y2)/(y+4)\]Solve for y.\[(y+4)(x)=((3y2)/(y+4))(y+4)\]\[(y+4)(x)=3y2\]3y 3y\[(y+4)(x)3y=2\] /x /x\[y+43y=2/x\]\[2y+4=2/x\] 4 4\[2y=(2/x)4\]/2 /2\[y=((2/x)4)/2\]It'll look ugly only because it's an inverse function. Although, after graphing it I may be wrong altogether.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[f^{1}(x)=f(y)\] \[x=(3y−2)/(y+4)\]\[x(y+4)=(3y−2)\]\[xy+4x3y+2=0\]\[y(x3)+(4x+2)=0\]\[y(x3)=(4x+2)\]\[y=\frac{4x+2}{3x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For b, \[x=\sqrt{y1}\]\[x^2=y1\]\[y=x^2+1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you so much both of you (:

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but im confused both of you got a different answer for A

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0He's right, I didn't distribute my x in one of my steps.
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