## anonymous 4 years ago simplify (3/b - 27/b^2 ) / (17/b^2)

1. anonymous

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2. anonymous

can someone explain to me how to do this ?

3. anonymous

3b-27/17 =3(b-9)/17

4. anonymous

how?

5. anonymous

first take 3/b it can also be written as 3b/b^2. isn't t?

6. anonymous

no its just 3/b

7. anonymous

ohh

8. anonymous

never mind haha

9. anonymous

my bad. so after that ?

10. anonymous

So now you have $\frac{\frac{3b-27}{b^2}}{\frac{17}{b^2}}$, correct?

11. anonymous

yeah

12. anonymous

We can write this as $\frac{3b-27}{b^2} \div \frac{17}{b^2}$ which is equal to $\frac{3b-27}{b^2} \times \frac{b^2}{17}$ here the b^2 cancels out and by factorizing the top we are left with $\frac{3(b-9)}{17}$

13. anonymous

ohhhhh ok thanks!

14. anonymous

=[(3/b)-(27/b^2)]/(17/b^2) =[(3/b)-(27/b^2)]x(b^2/17) =(3b/17)-(27/17) =(3b-27)/17

15. anonymous

which is equal to: 3(b-9)/17