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anonymous

  • 5 years ago

simplify (3/b - 27/b^2 ) / (17/b^2)

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  1. anonymous
    • 5 years ago
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    |dw:1326869774755:dw|

  2. anonymous
    • 5 years ago
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    can someone explain to me how to do this ?

  3. anonymous
    • 5 years ago
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    3b-27/17 =3(b-9)/17

  4. anonymous
    • 5 years ago
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    how?

  5. anonymous
    • 5 years ago
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    first take 3/b it can also be written as 3b/b^2. isn't t?

  6. anonymous
    • 5 years ago
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    no its just 3/b

  7. anonymous
    • 5 years ago
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    ohh

  8. anonymous
    • 5 years ago
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    never mind haha

  9. anonymous
    • 5 years ago
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    my bad. so after that ?

  10. anonymous
    • 5 years ago
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    So now you have \[\frac{\frac{3b-27}{b^2}}{\frac{17}{b^2}}\], correct?

  11. anonymous
    • 5 years ago
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    yeah

  12. anonymous
    • 5 years ago
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    We can write this as \[\frac{3b-27}{b^2} \div \frac{17}{b^2}\] which is equal to \[\frac{3b-27}{b^2} \times \frac{b^2}{17}\] here the b^2 cancels out and by factorizing the top we are left with \[\frac{3(b-9)}{17}\]

  13. anonymous
    • 5 years ago
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    ohhhhh ok thanks!

  14. anonymous
    • 5 years ago
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    =[(3/b)-(27/b^2)]/(17/b^2) =[(3/b)-(27/b^2)]x(b^2/17) =(3b/17)-(27/17) =(3b-27)/17

  15. anonymous
    • 5 years ago
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    which is equal to: 3(b-9)/17

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