anonymous
  • anonymous
simplify (3/b - 27/b^2 ) / (17/b^2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
|dw:1326869774755:dw|
anonymous
  • anonymous
can someone explain to me how to do this ?
anonymous
  • anonymous
3b-27/17 =3(b-9)/17

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anonymous
  • anonymous
how?
anonymous
  • anonymous
first take 3/b it can also be written as 3b/b^2. isn't t?
anonymous
  • anonymous
no its just 3/b
anonymous
  • anonymous
ohh
anonymous
  • anonymous
never mind haha
anonymous
  • anonymous
my bad. so after that ?
anonymous
  • anonymous
So now you have \[\frac{\frac{3b-27}{b^2}}{\frac{17}{b^2}}\], correct?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
We can write this as \[\frac{3b-27}{b^2} \div \frac{17}{b^2}\] which is equal to \[\frac{3b-27}{b^2} \times \frac{b^2}{17}\] here the b^2 cancels out and by factorizing the top we are left with \[\frac{3(b-9)}{17}\]
anonymous
  • anonymous
ohhhhh ok thanks!
anonymous
  • anonymous
=[(3/b)-(27/b^2)]/(17/b^2) =[(3/b)-(27/b^2)]x(b^2/17) =(3b/17)-(27/17) =(3b-27)/17
anonymous
  • anonymous
which is equal to: 3(b-9)/17

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