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anonymous
 5 years ago
A and B are playing the following game.A starts and tosses a fair coin .if outcome is head.A wins.if A fails to win ,passes the coin to B,who then attempts to win on her toss as before,a win occurs if the outcome is head.they continue to toss the coin back and forth until one of them wins.what is the probability of A winning the game?
anonymous
 5 years ago
A and B are playing the following game.A starts and tosses a fair coin .if outcome is head.A wins.if A fails to win ,passes the coin to B,who then attempts to win on her toss as before,a win occurs if the outcome is head.they continue to toss the coin back and forth until one of them wins.what is the probability of A winning the game?

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King
 5 years ago
Best ResponseYou've already chosen the best response.0tomas suppose in his first chance itself A gets a head,he wins so there probability is 1/2 ....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no... what if he don't?

King
 5 years ago
Best ResponseYou've already chosen the best response.0s it like x+x^2+x^3+...+x^n?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01/2+1/2*1/2*1/2+1/2*1/2*1/2*1/2*1/2+... H TTH TTTTH ...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Tomas did a nice job, look again, the first blank is for A winning on first flip ______ or 1/2 the second blank is for A winning on the second flip _______ 1/2 times 1/2 the third blank is for A winning on the third flip _______ 1/2 times 1/2 times 1/2 and so on and so on ..... forever .... since it is a geometric series..... These are really challenging questions, using probability and precalculus at the same time .... very challenging and frustrating at times

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0second blank should be 1/2*1/2*1/2 because first throw: first player get tails second throw: second player MUST get tails too, because we are searching for probability that first wons third throw: first player gets heads and so on

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey that is confusing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, these are very tough questions ...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0which book will help?or any approach?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you have a textbook?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you notice geometric series in this problem? do you know how to use them?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ya,nagar and das....nd hammond

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u may explain the g.p also

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0some good videos on Khan Academy http://www.khanacademy.org/#browse

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think he don't even understand what we said?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here is a video on the second question that you asked today http://www.khanacademy.org/video/expectedvalueex?playlist=Probability

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here is a video on the first question from today http://www.khanacademy.org/video/compoundprobabilityofindependentevents?playlist=Probability

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tomas u can help i guess
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