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anonymous
 5 years ago
I am sure there is someone here that can easily tackle this problem! Factor: 3x^(1/2)+9x^91/2)81^(3/2)
I panic when I see negative fractional exponents! And my factoring skills are weak at best If you can explain any of the steps or the way you think about the problem I would greatly appreciate the advice.
anonymous
 5 years ago
I am sure there is someone here that can easily tackle this problem! Factor: 3x^(1/2)+9x^91/2)81^(3/2) I panic when I see negative fractional exponents! And my factoring skills are weak at best If you can explain any of the steps or the way you think about the problem I would greatly appreciate the advice.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[ 3x^{\frac{1}{2}}+9x^{\frac{1}{2}}81^{\frac{3}{2}}\] like this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I was thinking that an x^(1/2) If 81x^(3/2) could be rewritten as 81x(3(1/2)) and 3x(1/2) could be rewritten as 3x^(1(1/2))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can write out what this means without negative exponents, but i cannot see how to factor it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops that an x^(1/2) could be factored out *

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh wait, is there an x in the last term?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[3x^{\frac{1}{2}}+9x^{\frac{1}{2}}81x^{\frac{3}{2}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh yikes I overlooked that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0good catch. I looked over it so quickly the first time I missed the omission.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok that is a whole different story. first off you can factor a 3 out of each term, then also perhaps an \[x^{\frac{1}{2}}\] if you like. lets try it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Great I get coefficients of 1 3 and 27

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[3x^{\frac{1}{2}}(x^{1}+3+27x^{2})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now i wonder if we can go further...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cool that exactly where I am at the moment as well

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i think it is \[27x^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because \[\frac{3}{2}\frac{1}{2}=2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i cannot see how to factor the second part, so i think you are done at that step

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so the exponents are not being multiplied in this case

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I was thinking it was 27x^(3(1/2))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i was off by a minus sign, should be \[27x^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you multiply you add the exponents

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so \[3x^{\frac{1}{2}}\times 27x^{2}=81x^{\frac{1}{2}+(2)}=81x^{\frac{3}{2}}\] which is what you want

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok I think I see how that works so x^(1/2)x^2(2/2) = x^(1/2)x^(4/4) or x^(3/2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you so much for your help! This really helped clarify the concept for me.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you don't need to change the denominator is 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops meant (2(2/2) = (4/2)
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