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anonymous
 4 years ago
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anonymous
 4 years ago
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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How do I solve these questions

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I was given y2/y1 = y3/y2 then it is a exponential function and if its y2  y1 = y3y2 it is a linear function

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm just confused by these problems it also brings up delta x = x2  x1 and x2  x1 = x3  x2 Do these equations have to do wit the continuity of the function I'm trying to determine?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm not trying to get the answer for this problem I simply just want a better understanding of the problem itself

sasogeek
 4 years ago
Best ResponseYou've already chosen the best response.0probably, i'm not an expert at this but i'll try to get u someone who can help :)

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2It's not that difficult. I just haven't done this in a while so I'm going to contact a resource and get back to you.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Okay, I'm back. It really is easy and I should have remembered how to do it, but I got stuck on one thing.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2Basically, when dealing with exponential functions, they have the general form: y = ab^x, where a = initial value and b = base or growth factor. If b > 1, then the function is exponential growth. If 0 < b < 1, meaning if b is between 0 and 1, then the function is exponential decay. Also, b = 1 + r, where r = the percent rate of change. In this particular case, we have the set of table values for 3a). To find out if the function is exponential, simply take the f(x) values and divide the values like so: 43.5/87 = 0.5 87/174 = 0.5 The fact that both divisions equal 0.5 indicates an exponential function. Using the formula for exponential functions, y = ab^x, we first find a. Since x = 0 and 6 y = f(x) = 43.5, 43.5 = a, the initial value. Now, we must find b. To find b, plug in a given point along with a into the formula, then solve for b as follows: y = ab^x 87 = 43.5b^1 87/43.5 = b 2 = b So, now that we've found a and b, we can now write our exponential formula: y = 43.5(2)^x 3b) is just a linear equation. I'm sure you can figure that one out yourself.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.2If you have any questions, let me know.

sasogeek
 4 years ago
Best ResponseYou've already chosen the best response.0thanks hero, I'm not too good at this but that made a lot of sense :) thanks :)
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