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anonymous
 4 years ago
help with algebra plz
anonymous
 4 years ago
help with algebra plz

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[11]{8}+\sqrt[6]{12}\sqrt[5]{2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0d sorry can u mention which root is over 12 and 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes :) 6 for 12 and 5 for 2

Hero
 4 years ago
Best ResponseYou've already chosen the best response.0put the roots in fraction form. That might help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohyou didnt have to give the answer :P i just wanted help with solving it :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i just dont know how to solve this with the number superscripted on the square root.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1326910735854:dw

wasiqss
 4 years ago
Best ResponseYou've already chosen the best response.0u want answer in decimal or fraction form cox this cant b evaluated in fraction form

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay you want a reduce form under radical right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0fibonacci girl sorry ......just saw that you wanted the steps also

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and i dont want to you guys to do the work for me, i just want to know how to do this. it is driving me crazyy

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0fibonacci girl do you know how to use logs

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's admirable :) Okay tell me do you know indices?

wasiqss
 4 years ago
Best ResponseYou've already chosen the best response.0hey we can make under root 2 common,

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No logarithm needed, IMO.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay do you know that \(\huge \sqrt[a]{b} = b^\frac 1a \) ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh yeah!! i learned that in precalc like 2 months ago!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Good, so now it's time to apply what you learned, lets see, your problems is \( \sqrt[11]{8}+\sqrt[6]{12}\sqrt[5]{2} \) lets assume the first term first \( \large\sqrt[11]{8} = 2^ \frac 3{11} \) can you follow this?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Good, now what about \(\sqrt[6]{12} \)? I want you to do this.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think i get it now :) let me try to solve on my own and then ill show what i did

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have gotten this far: \[8^{1/11}+2^{1/6}2^{1/5}\] 1/11+1/6=17/66 \[10^{17/66}2^{1/5}\] 17/661/5=19/330 \[8^{19/330}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That doesn't seem to be correct.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[ \huge \sqrt[11]{8}+\sqrt[6]{12}\sqrt[5]{2} \] \[\huge \implies 2^ \frac 3{11}+2^\frac 1{3}\times 3^\frac 162^\frac 15\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i have 0 idea how you got that :(

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[1/\sqrt[99]{16}\] is this right??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how foolsformath got those numbers and is my answer correct??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dang it :/ im never gonna get this

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you help me please?

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0Sure, but can u wait for about a hour or so?

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.0Cool. C ya later then! :)
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