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anonymous

  • 5 years ago

help with algebra plz

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  1. anonymous
    • 5 years ago
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    \[\sqrt[11]{8}+\sqrt[6]{12}-\sqrt[5]{2}\]

  2. anonymous
    • 5 years ago
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    d sorry can u mention which root is over 12 and 2

  3. anonymous
    • 5 years ago
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    yes :) 6 for 12 and 5 for 2

  4. Hero
    • 5 years ago
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    put the roots in fraction form. That might help

  5. anonymous
    • 5 years ago
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    its 1.5724

  6. anonymous
    • 5 years ago
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    ohyou didnt have to give the answer :P i just wanted help with solving it :)

  7. Hero
    • 5 years ago
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    She wants actual steps

  8. anonymous
    • 5 years ago
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    i just dont know how to solve this with the number superscripted on the square root.

  9. anonymous
    • 5 years ago
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    |dw:1326910735854:dw|

  10. wasiqss
    • 5 years ago
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    u want answer in decimal or fraction form cox this cant b evaluated in fraction form

  11. anonymous
    • 5 years ago
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    Okay you want a reduce form under radical right?

  12. anonymous
    • 5 years ago
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    fibonacci girl sorry ......just saw that you wanted the steps also

  13. anonymous
    • 5 years ago
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    radical form :)

  14. anonymous
    • 5 years ago
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    and i dont want to you guys to do the work for me, i just want to know how to do this. it is driving me crazyy

  15. anonymous
    • 5 years ago
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    fibonacci girl do you know how to use logs

  16. anonymous
    • 5 years ago
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    That's admirable :) Okay tell me do you know indices?

  17. wasiqss
    • 5 years ago
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    hey we can make under root 2 common,

  18. anonymous
    • 5 years ago
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    no :/

  19. anonymous
    • 5 years ago
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    No logarithm needed, IMO.

  20. anonymous
    • 5 years ago
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    Okay do you know that \(\huge \sqrt[a]{b} = b^\frac 1a \) ?

  21. anonymous
    • 5 years ago
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    oh yeah!! i learned that in precalc like 2 months ago!

  22. anonymous
    • 5 years ago
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    Good, so now it's time to apply what you learned, lets see, your problems is \( \sqrt[11]{8}+\sqrt[6]{12}-\sqrt[5]{2} \) lets assume the first term first \( \large\sqrt[11]{8} = 2^ \frac 3{11} \) can you follow this?

  23. anonymous
    • 5 years ago
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    yes i can :)

  24. anonymous
    • 5 years ago
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    Good, now what about \(\sqrt[6]{12} \)? I want you to do this.

  25. anonymous
    • 5 years ago
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    \[12^{1/6}\]

  26. anonymous
    • 5 years ago
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    i think i get it now :) let me try to solve on my own and then ill show what i did

  27. anonymous
    • 5 years ago
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    That's great :)

  28. anonymous
    • 5 years ago
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    i have gotten this far: \[8^{1/11}+2^{1/6}-2^{1/5}\] 1/11+1/6=17/66 \[10^{17/66}-2^{1/5}\] 17/66-1/5=19/330 \[8^{19/330}\]

  29. anonymous
    • 5 years ago
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    That doesn't seem to be correct.

  30. anonymous
    • 5 years ago
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    \[ \huge \sqrt[11]{8}+\sqrt[6]{12}-\sqrt[5]{2} \] \[\huge \implies 2^ \frac 3{11}+2^\frac 1{3}\times 3^\frac 16-2^\frac 15\]

  31. anonymous
    • 5 years ago
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    i have 0 idea how you got that :(

  32. anonymous
    • 5 years ago
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    \[1/\sqrt[99]{16}\] is this right??

  33. saifoo.khan
    • 5 years ago
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    Where are u stuck>

  34. anonymous
    • 5 years ago
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    how foolsformath got those numbers and is my answer correct??

  35. saifoo.khan
    • 5 years ago
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    umm.. no.

  36. anonymous
    • 5 years ago
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    dang it :/ im never gonna get this

  37. saifoo.khan
    • 5 years ago
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    Sad. :(

  38. anonymous
    • 5 years ago
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    can you help me please?

  39. saifoo.khan
    • 5 years ago
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    Sure, but can u wait for about a hour or so?

  40. anonymous
    • 5 years ago
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    yes

  41. saifoo.khan
    • 5 years ago
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    Cool. C ya later then! :)

  42. anonymous
    • 5 years ago
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    thank you?

  43. anonymous
    • 5 years ago
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    :)

  44. saifoo.khan
    • 5 years ago
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    No Problem?

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