anonymous
  • anonymous
help with algebra plz
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\sqrt[11]{8}+\sqrt[6]{12}-\sqrt[5]{2}\]
anonymous
  • anonymous
d sorry can u mention which root is over 12 and 2
anonymous
  • anonymous
yes :) 6 for 12 and 5 for 2

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More answers

Hero
  • Hero
put the roots in fraction form. That might help
anonymous
  • anonymous
its 1.5724
anonymous
  • anonymous
ohyou didnt have to give the answer :P i just wanted help with solving it :)
Hero
  • Hero
She wants actual steps
anonymous
  • anonymous
i just dont know how to solve this with the number superscripted on the square root.
anonymous
  • anonymous
|dw:1326910735854:dw|
wasiqss
  • wasiqss
u want answer in decimal or fraction form cox this cant b evaluated in fraction form
anonymous
  • anonymous
Okay you want a reduce form under radical right?
anonymous
  • anonymous
fibonacci girl sorry ......just saw that you wanted the steps also
anonymous
  • anonymous
radical form :)
anonymous
  • anonymous
and i dont want to you guys to do the work for me, i just want to know how to do this. it is driving me crazyy
anonymous
  • anonymous
fibonacci girl do you know how to use logs
anonymous
  • anonymous
That's admirable :) Okay tell me do you know indices?
wasiqss
  • wasiqss
hey we can make under root 2 common,
anonymous
  • anonymous
no :/
anonymous
  • anonymous
No logarithm needed, IMO.
anonymous
  • anonymous
Okay do you know that \(\huge \sqrt[a]{b} = b^\frac 1a \) ?
anonymous
  • anonymous
oh yeah!! i learned that in precalc like 2 months ago!
anonymous
  • anonymous
Good, so now it's time to apply what you learned, lets see, your problems is \( \sqrt[11]{8}+\sqrt[6]{12}-\sqrt[5]{2} \) lets assume the first term first \( \large\sqrt[11]{8} = 2^ \frac 3{11} \) can you follow this?
anonymous
  • anonymous
yes i can :)
anonymous
  • anonymous
Good, now what about \(\sqrt[6]{12} \)? I want you to do this.
anonymous
  • anonymous
\[12^{1/6}\]
anonymous
  • anonymous
i think i get it now :) let me try to solve on my own and then ill show what i did
anonymous
  • anonymous
That's great :)
anonymous
  • anonymous
i have gotten this far: \[8^{1/11}+2^{1/6}-2^{1/5}\] 1/11+1/6=17/66 \[10^{17/66}-2^{1/5}\] 17/66-1/5=19/330 \[8^{19/330}\]
anonymous
  • anonymous
That doesn't seem to be correct.
anonymous
  • anonymous
\[ \huge \sqrt[11]{8}+\sqrt[6]{12}-\sqrt[5]{2} \] \[\huge \implies 2^ \frac 3{11}+2^\frac 1{3}\times 3^\frac 16-2^\frac 15\]
anonymous
  • anonymous
i have 0 idea how you got that :(
anonymous
  • anonymous
\[1/\sqrt[99]{16}\] is this right??
saifoo.khan
  • saifoo.khan
Where are u stuck>
anonymous
  • anonymous
how foolsformath got those numbers and is my answer correct??
saifoo.khan
  • saifoo.khan
umm.. no.
anonymous
  • anonymous
dang it :/ im never gonna get this
saifoo.khan
  • saifoo.khan
Sad. :(
anonymous
  • anonymous
can you help me please?
saifoo.khan
  • saifoo.khan
Sure, but can u wait for about a hour or so?
anonymous
  • anonymous
yes
saifoo.khan
  • saifoo.khan
Cool. C ya later then! :)
anonymous
  • anonymous
thank you?
anonymous
  • anonymous
:)
saifoo.khan
  • saifoo.khan
No Problem?

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