anonymous 5 years ago help with algebra plz

1. anonymous

$\sqrt[11]{8}+\sqrt[6]{12}-\sqrt[5]{2}$

2. anonymous

d sorry can u mention which root is over 12 and 2

3. anonymous

yes :) 6 for 12 and 5 for 2

4. Hero

put the roots in fraction form. That might help

5. anonymous

its 1.5724

6. anonymous

ohyou didnt have to give the answer :P i just wanted help with solving it :)

7. Hero

She wants actual steps

8. anonymous

i just dont know how to solve this with the number superscripted on the square root.

9. anonymous

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10. wasiqss

u want answer in decimal or fraction form cox this cant b evaluated in fraction form

11. anonymous

Okay you want a reduce form under radical right?

12. anonymous

fibonacci girl sorry ......just saw that you wanted the steps also

13. anonymous

14. anonymous

and i dont want to you guys to do the work for me, i just want to know how to do this. it is driving me crazyy

15. anonymous

fibonacci girl do you know how to use logs

16. anonymous

That's admirable :) Okay tell me do you know indices?

17. wasiqss

hey we can make under root 2 common,

18. anonymous

no :/

19. anonymous

No logarithm needed, IMO.

20. anonymous

Okay do you know that $$\huge \sqrt[a]{b} = b^\frac 1a$$ ?

21. anonymous

oh yeah!! i learned that in precalc like 2 months ago!

22. anonymous

Good, so now it's time to apply what you learned, lets see, your problems is $$\sqrt[11]{8}+\sqrt[6]{12}-\sqrt[5]{2}$$ lets assume the first term first $$\large\sqrt[11]{8} = 2^ \frac 3{11}$$ can you follow this?

23. anonymous

yes i can :)

24. anonymous

Good, now what about $$\sqrt[6]{12}$$? I want you to do this.

25. anonymous

$12^{1/6}$

26. anonymous

i think i get it now :) let me try to solve on my own and then ill show what i did

27. anonymous

That's great :)

28. anonymous

i have gotten this far: $8^{1/11}+2^{1/6}-2^{1/5}$ 1/11+1/6=17/66 $10^{17/66}-2^{1/5}$ 17/66-1/5=19/330 $8^{19/330}$

29. anonymous

That doesn't seem to be correct.

30. anonymous

$\huge \sqrt[11]{8}+\sqrt[6]{12}-\sqrt[5]{2}$ $\huge \implies 2^ \frac 3{11}+2^\frac 1{3}\times 3^\frac 16-2^\frac 15$

31. anonymous

i have 0 idea how you got that :(

32. anonymous

$1/\sqrt[99]{16}$ is this right??

33. saifoo.khan

Where are u stuck>

34. anonymous

how foolsformath got those numbers and is my answer correct??

35. saifoo.khan

umm.. no.

36. anonymous

dang it :/ im never gonna get this

37. saifoo.khan

38. anonymous

39. saifoo.khan

Sure, but can u wait for about a hour or so?

40. anonymous

yes

41. saifoo.khan

Cool. C ya later then! :)

42. anonymous

thank you?

43. anonymous

:)

44. saifoo.khan

No Problem?