Here mertsj.
After your friend confirms the 11 a.m. get-together at the library, you receive an email with some specific questions, so you know what to expect when you get there.
Here's the email:
Your task
Help your friend out by doing the following for each of the questions in the email:
Answer the question in complete sentences, as if you were explaining it to your friend.
Create a unique teaching example to demonstrate what you explained in words. Work through this example step by step.
Create a unique practice example. Provide the problem and the answer. Because you'd like your fri

- anonymous

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- anonymous

1:If oyu know two lengths of a right triangle how do you find the third.
2:Can i find two missing side lengths of a right triangle if i only knew 1 length and one angle,
3:Can i find two missing angles if i knew some of the side lengths of a right triangle.
4:what makes a triangle a special right triangle?how can it being special help me find side lengths?

- anonymous

the 1,2,3 and 4 are the email

- anonymous

did you do #1?

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## More answers

- anonymous

i can say it in simple english if you like

- anonymous

sort of..... i think Mertsj could help alot, but you can give it a try

- anonymous

i need to have an example for each and a teaching example for each.

- anonymous

to find the hypotenuse:
square the lengths of the two legs,
and the squares together,
then take the square root
to find one of the legs:
square the length of the hypotenuse,
square the length of the leg you know,
subtract that number from the square of the hypotenuse,
take the square root

- anonymous

ok so i can use one of those as the lesson for 1 and i need to make an example now.

- Mertsj

Hang on. i'm on the phone.

- anonymous

ok

- Mertsj

1. You can find any side of a right triangle of a right triangle if you know two of the sides by using the pythagorean theorem. The pythagorean theorem is c^2=a^2 + b^2. In this equation a and b and the lengths of the sides that form the right angle. c is the long side which is called the hypotenuse.

- Mertsj

For example, if you have a right triangle such as this one:|dw:1326916895230:dw|

- anonymous

ok i know that but for the second part of the instructions it says create an example using two different sides to find the length of a leg.

- anonymous

tha part did not copy sorry, but thats what it says

- anonymous

and i cannot use pictures.

- Mertsj

Oh no. Scratch that example. It says to find the length of a leg. I'll start over.

- anonymous

Create a unique teaching example to demonstrate what you explained in words. Work through this example step by step.
Create a unique practice example. Provide the problem and the answer. Because you'd like your friend to show their understanding of what you taught, make the practice example different from the teaching example. For example, if the teaching example for #1 was missing the hypotenuse, have the practice example missing one of the legs. Or, if the teaching example for #4 used the sin ratio, have the practice example use the cosine or tangent ratio.

- anonymous

thats the instructions after answering the question.

- Mertsj

|dw:1326917117864:dw|

- Mertsj

Here we can find the missing leg, b, by saying
6^2+b^2=10^2
36+b^2 = 100
b^2=64
b=8
So the missing leg is 8
Now you try this one:
|dw:1326917349832:dw|

- Mertsj

The answer is 13. See if you can get it.

- anonymous

but see i cant use pictures.. so should i put the triangles in letter form?

- Mertsj

Is that enough?

- Mertsj

Ok. Substitute this for the first picture:
I have a right triangle which has one leg equal to 6. The other leg is missing but I know the hypotenuse is 10.

- Mertsj

Substitute this for the second picture:
In this right triangle, the two legs are 5 and 12. Can you find the hypotenuse? The answer is 13. See if you can get it.

- anonymous

so should i use the first picture with my lesson to the person?

- anonymous

so is this good for number 1 you think?
1. You can find any side of a right triangle if you know two of the sides by using the Pythagorean Theorem. The Pythagorean Theorem is c^2=a^2 + b^2. In this equation a and b and the lengths of the sides that form the right angle. c is the long side which is called the hypotenuse. An example could be if the length of one leg in a triangle is 3 and the other is 4, then do 3^2+4^2=C^2. So 9+16=25. Then you take the square root of 25, and you get your hypotenuse which would be 5.
Example: Here now you try this one. I have a right triangle which has one leg equal to 6. The other leg is missing but I know the hypotenuse is 10. The answer is 13 but can you try and solve this?

- anonymous

is that good?????

- Mertsj

hang on

- anonymous

ok...

- Mertsj

That's very good. Sorry it took so long. I was on the phone again.

- Mertsj

Oh. except your example. You should say that the answer to that one is 8

- anonymous

is 8 correct?

- Mertsj

Because 6^2+*^2 = 10^2

- Mertsj

Yes. 8 is correct.

- anonymous

ok..now im trying to work on the others but i do not understand what i should do.

- Mertsj

What are the others?

- anonymous

numbers 2,3 and 4.

- anonymous

2:Can i find two missing side lengths of a right triangle if i only knew 1 length and one angle,
3:Can i find two missing angles if i knew some of the side lengths of a right triangle.
4:what makes a triangle a special right triangle?how can it being special help me find side lengths?

- Mertsj

2:Can i find two missing side lengths of a right triangle if i only knew 1 length and one angle,
Yes. You can find the missing sides if you know one side and one angle. You can use the trig function that involves the side of the triangle that you know and the side of the triangle that you are trying to find.

- Mertsj

The sin function is the side opposite the known angle divided by the hypotenuse.
The cos function is the side adjacent the known angle divided by the hypotenuse.
The tan function is the side opposite the known angle divided by the side adjacent.

- anonymous

is that part of the lesson?

- Mertsj

I am not sure what you have to do. Do you have to answer all of these questions the way you did the first one...by explaining how to do them in an email to a friend complete with examples?

- anonymous

yes.

- Mertsj

Well then, how much are we supposed to assume that your friend knows?

- Mertsj

Do we assume that she knows the trig functions and their definitions?

- anonymous

thats where i get confused because they do not explain to well. i will never take another online math class..haha...and he knows nothin. Thats why he is asking because he is taking a teset. so ihave to teach it to him

- Mertsj

So you are actually trying to teach this to someone in an email?

- anonymous

yes. Basically. not into depth but to give them a general idea to know how to do it

- Mertsj

So...Why doesn't he just get on this website and ask his questions?

- Mertsj

If he has email, he has access.

- anonymous

its not a real person. haha!. its fake and its being sent to my teacher so she knows that i understand how to teach what i have learned. But i dont so i am on here asking for help trying to teach it back. See what i mean?

- anonymous

its an assignment

- Mertsj

That's what I thought but then you said otherwise. So continuing with the question...

- Mertsj

Start with the acute angle that you know. Identify the known side in relation to that angle. Then identify the side that you want to find. Choose the appropriate function and substitute the values.
For example if you know the angle is 30 degrees and you know the side opposite the 30 degree angle is 10 and you want to find the hypotenuse then use the sin function.
Write sin 30 = 10/h and solve that equation.
.5=10/h
.5h=10
h=20
Now you try this one: In a right triangle there is a 45 degree angle. The hypotenuse is 10. Find the side adjacent to the 45 degree angle. The answer is 7.07. See if you can get it.

- Mertsj

Ok. Number 3 is similar. See if you can do it.

- anonymous

no. because it does not specify how many side lengths you have.????

- anonymous

see i dont understand. but i will try and figure it out. i hope/.

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