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oooops, i didn't mean dy/dx, i meant the integration sign
aah - i thought that might be the case
if there was the correct notification, would that be correct?
split this up into partial fractions we get INT (1 - 7 ) dx ----- 3(x+3)
can you continue from there?
you rresult is not correct
I don't understand what you have done, where has this 7 and this 3(x+3) came from?
sorry guy - i copied the question down wrongly - i'll hav e another look at it
ok, i was a bit worried when a 7 randomly appeared lol thanks for helping me out, im currently revising for an exam :D
first do long division to obtain INT 1 / 3(3x + 1) + INT 1/3 = 1/3 INT 1/ (3x+1) + x/3
dividing 3x + 2 by 9x+ 3 gives 1/3 + 1 / (9x+ 3)
am i right?
must admit my integration is pretty rusty
lol, mine too, and i have an exam on it in about 36 hours xD
I thought that the question would involve natural logs when integrating (like when 1/x is integrated) doesn't it?
yes - so integrating 1/3 INT 1/ (3x+1) = 1/9 ln| 3x+1| so finally answer is x/3 + 1/9 ln| 3x+1| + C
yea thats correct - i checked it out on wolframalpha
ok, thanks for your help :D