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oooops, i didn't mean dy/dx, i meant the integration sign

aah - i thought that might be the case

if there was the correct notification, would that be correct?

split this up into partial fractions
we get
INT (1 - 7 ) dx
-----
3(x+3)

can you continue from there?

you rresult is not correct

I don't understand what you have done, where has this 7 and this 3(x+3) came from?

sorry guy - i copied the question down wrongly - i'll hav e another look at it

kind of a guess: is it this instead?

or...

first do long division to obtain
INT 1 / 3(3x + 1) + INT 1/3
= 1/3 INT 1/ (3x+1) + x/3

dividing 3x + 2 by 9x+ 3 gives 1/3 + 1 / (9x+ 3)

am i right?

must admit my integration is pretty rusty

lol, mine too, and i have an exam on it in about 36 hours xD

yes - so integrating 1/3 INT 1/ (3x+1) = 1/9 ln| 3x+1|
so finally answer is x/3 + 1/9 ln| 3x+1| + C

yea thats correct - i checked it out on wolframalpha

ok, thanks for your help :D

yw