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anonymous
 5 years ago
Can anyone solve this insanity of Simplifying Exponent Expressions?????? Its (3x^1 y^2)(2x^4 y^3) ???????????/
anonymous
 5 years ago
Can anyone solve this insanity of Simplifying Exponent Expressions?????? Its (3x^1 y^2)(2x^4 y^3) ???????????/

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(3x^{1} y^{2})(2x^4 y^{3}) \] it is just bookkeeping. add the exponents

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[6x^{1+4}y^{23}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But it says to write it as positive exponents

Hero
 5 years ago
Best ResponseYou've already chosen the best response.0I personally hate negative exponents. You'll never see a negative exponent in any of my solutions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok satellite has already done all the hard work, the rest is easy if you wish to write it in terms of positive exponents.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here is what Satellite got to: \[6x^{3}y^{5}\] then you know that a negative exponent means a fraction  i.e. \[a^{b} = \frac{1}{a^b}\] so we have \[\frac{6x^3}{y^5}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when multiplying, add the indices, when raising to the power multiply the indices...

Hero
 5 years ago
Best ResponseYou've already chosen the best response.0negative exponent actually means means "inverse". so a^b really means inverse of a^b which equals 1/a^b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can I throw another 1 @ ya?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, it's the multiplicative inverse isn't it: a^(b) has multiplicative inverse a^(b). In the real number field this is equal to 1/a^b. However, in groups for example, there's no concept of a number so we stick to a^(1) as the inverse of a. Since we are in the real numbers, a^b has inverse a^(b).
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