anonymous
  • anonymous
Why would f(1/4) be undefined?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Anikate
  • Anikate
well we no that the answer is f/4
Anikate
  • Anikate
there is no equal sign
asnaseer
  • asnaseer
your question is not complete. you need to tel us what f(x) is defined to be.

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anonymous
  • anonymous
I have to explain why why f(1) = 3, f(0) = 2, and f(-1) = 1, but why f(1/4) is defined
anonymous
  • anonymous
*undefined
asnaseer
  • asnaseer
have you been given the expression for f(x) in terms of x?
anonymous
  • anonymous
in the 4x^2+ 7x - 2/ 4x-1
asnaseer
  • asnaseer
ok - now it makes sense
anonymous
  • anonymous
i simplified it to x + 2/ 1 XD
asnaseer
  • asnaseer
if you look at the last term, you have a division by "4x-1". what will "4x-1" equate to when x=1/4?
asnaseer
  • asnaseer
\[f(x)=4x^2+7x-\frac{2}{4x-1}\]
anonymous
  • anonymous
ohhh it would be 0
asnaseer
  • asnaseer
correct - so you would be dividing by zero - which is undefined.
asnaseer
  • asnaseer
BTW: your simplification to x + 2/ 1 is not correct.
anonymous
  • anonymous
ahhhh :( what I do wrong?
asnaseer
  • asnaseer
can you please try and explain to me step by step what you did so that I can spot where you went wrong
anonymous
  • anonymous
I factored to get (x+2)(4x-1)/4x-1 then canceled out common factors and got x+2/1
asnaseer
  • asnaseer
your factorisation in wrong. remember the last term is a fraction.
asnaseer
  • asnaseer
\[\begin{align} f(x)&=4x^2+7x-\frac{2}{4x-1}\\ &=\frac{(4x-1)(4x^2+7x)-2}{4x-1} \end{align}\]
anonymous
  • anonymous
its supposed to be a rational expression o.O
anonymous
  • anonymous
it looks like this : 4x^2+ 7x - 2 -------------- 4x-1
asnaseer
  • asnaseer
so the equation is supposed to be:\[f(x)=\frac{4x^2+7x-2}{4x-1}\]
asnaseer
  • asnaseer
which can be factored as:\[f(x)=\frac{(x+2)(4x-1)}{4x-1}\]
anonymous
  • anonymous
yes :)
asnaseer
  • asnaseer
but you cannot cancel the 4x-1 because it would be like dividing top and bottom by zero when x=1/4
anonymous
  • anonymous
i just canceled out common factors that what my teacher told me :(
asnaseer
  • asnaseer
you can only do that if you are told that x can NEVER be equal to 1/4
asnaseer
  • asnaseer
in this case I believe x can take on ay real value from minus infinity to plus infinity
asnaseer
  • asnaseer
and it is undefined at x=1/4
asnaseer
  • asnaseer
was the question asking you why is this undefined at x=1/4?
anonymous
  • anonymous
yes
asnaseer
  • asnaseer
so then you can state that it undefined at x=1/4 because at x=1/4 we would be dividing by zero.
anonymous
  • anonymous
okay Thank you!!! XD Wish i could giv you more than one medal o.O lol
asnaseer
  • asnaseer
You're welcome - I'm glad I was able to explain it well enough for you.

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