anonymous
  • anonymous
on june 1 meg and john went swimming. if meg swims every third day and john swims every fith day when will they swim together?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
For this you need to find the LCM; lowest common multiple.
anonymous
  • anonymous
15.
anonymous
  • anonymous
Want to know hooooow?

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More answers

anonymous
  • anonymous
Use the least common multiple: the 15TH day.
anonymous
  • anonymous
you really stink at teachin huh!
anonymous
  • anonymous
?
anonymous
  • anonymous
not you everyone givin me the answer
anonymous
  • anonymous
Okay so you want to know how?
anonymous
  • anonymous
i got it
anonymous
  • anonymous
Okay.
anonymous
  • anonymous
wait how do i find the lcm
anonymous
  • anonymous
I'll give you an example okay? Because 5 and 3 are prime numbers
anonymous
  • anonymous
kk
anonymous
  • anonymous
|dw:1326931682544:dw|
anonymous
  • anonymous
Here I used 2, 8, and 12
anonymous
  • anonymous
You decide what number goes into all of the #s your are using, and then divide them all by that.
anonymous
  • anonymous
whats 26x3
anonymous
  • anonymous
When you are done you multiply all of the numbers on the side and the bottom together.
anonymous
  • anonymous
78
anonymous
  • anonymous
what is the lcm of 26 4 7
anonymous
  • anonymous
Ummmm.
anonymous
  • anonymous
how old are you
anonymous
  • anonymous
Why, how old do you think I am?
anonymous
  • anonymous
20;s
anonymous
  • anonymous
Lol
anonymous
  • anonymous
Ya know I'm not sure how to get the LCM, but I think you just multiply everything together. Don't hold me on that!
anonymous
  • anonymous
And I'm much younger than 20. If I was 20, I'd be a really stupid 20 year old.
anonymous
  • anonymous
Yeah. I guess.
anonymous
  • anonymous
I'm afraid I shall not.
anonymous
  • anonymous
Au revoir.
anonymous
  • anonymous
Et non.
anonymous
  • anonymous
?
anonymous
  • anonymous
Je m'appelle..... rien.
anonymous
  • anonymous
My name is nothing.
anonymous
  • anonymous
Goodbye.

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