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Soni-kay

  • 4 years ago

what is the range of f(x)=(x+4)^2 + 7?

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  1. Soni-kay
    • 4 years ago
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    |dw:1326932701655:dw|

  2. Soni-kay
    • 4 years ago
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    thanks

  3. Callum29
    • 4 years ago
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    \[f(x)=(x+4)^2 + 7 \geq 7\] for any value of x, which means that the lowest that f(x) can ever be is 7. But there is no upper limit since x is allowed to be anywhere on the real number line.

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