How do you find the area to a quadrilateral when it is not drawn to scale?

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How do you find the area to a quadrilateral when it is not drawn to scale?

Mathematics
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use given information, such as angles
Could we see a picture?
Given the dimensions, use the formula: A = bh

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|dw:1326933862189:dw|
The bottom number is a 6
Well, you have 4 right triangles and you are given the base and height of each triangle. So use A = 1/2 bh four times and add them together
|dw:1326934305163:dw|
I got an answer of 63. Is that correct
I forgot to divide by 2
So if I divide by 2, I get 31.5
That's what I got.
Thanks Mertsj and everyone else.
yw
The midpoint of line QR is M (-2,-6). One endpoint is R (4,-5). Find the coordinates of the other endpoint.
From 4 to -2 is left 6. go left 6 more to get to the other end. That would be -8 From -5 to -6 is down 1. Go down one more to get to the other end. That would be -7 So (-8,-7) Now graph it to see if it makes sense.
|dw:1326934761999:dw|
Yes, we got the same thing. This is a rise run problem. Thank you again
yw
|dw:1326934938444:dw|
In the diagram, PQRS is a rhombus. What are the values of x and y?
What is this thing?
so all sides are equal. So write that 2x=x+5 and solve it.
2x = x + 5 2x -x = 5 x = 5
yep
Is that all? It feels like I need to do more
How do I find y?
The diagonals of a rhombus are perpendicular and so now that you know one of the sides, you can use the pythagorean theorem
|dw:1326935721082:dw|
So the answer is 6?
yes
Thanks again. That's all for tonight. Again I thank you. Am I able to come on this site every night?
yw
yes
you can come whenever you want
So the answer is 6?
yes y = 6
It's a 6-8-10 right triangle. A multiple of the famous 3-4-5- pythagorean triple.

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