anonymous
  • anonymous
With a tailwind, a jet flew 2000 miles in 4 hours. The jet's return trip against the same wind required 5 hours. Find the jet's speed and the wind speed.
Mathematics
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anonymous
  • anonymous
With a tailwind, a jet flew 2000 miles in 4 hours. The jet's return trip against the same wind required 5 hours. Find the jet's speed and the wind speed.
Mathematics
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
(jetspeed + windspeed) * 4 = 2000 = (jetspeed - windspeed)*5
JamesJ
  • JamesJ
Suppose that with no wind the jet's speed is v. Let the wind have speed w. For the first leg of the trip, the speed of the jet is v + w because the wind is assisting the jet. Now, speed = (distance)/(time) hence v + w = 2000/4 = 500 For the return trip, the speed of the jet is v - w because the wind is working against the jet. Hence v - w = 2000/5 = 400 Therefore you have two simultaneous equations: v + w = 500 v - w = 400 Now solve them to find v and w.

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