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ok, the question is to express:\[4(\frac{z}{8})+\frac{z}{2}\]as:\[\frac{4z}{A}\]
btw the answer is not 8 or 1

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so start by simplifying the first expression as follows:\[4(\frac{z}{8})+\frac{z}{2}=\frac{z}{2}+\frac{z}{2}=z\]now, the only way that \(\frac{4z}{A}=z\) is if A=4
I need to go now - hopefully you understood the method above.

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