anonymous
  • anonymous
A coin is tossed 7 times. Find the probablility of getting exactly 4 heads.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
how many possible ways are there to toss 7 coins? how many of them end up with exactly 7 heads?
anonymous
  • anonymous
there are 2*2*2*2*2*2*2 = 2^7 different cointoss possibilities. (7 choose 4) of them = (7!)/(4!*(7-4)!) of them result in exactly 4 heads.
anonymous
  • anonymous
all 128 outcomes are equally likely, and 35 of them result in 4H3T, so the answer is 35/128.

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