factor the four term polynomial by grouping x^3+6x^2+8x+48

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factor the four term polynomial by grouping x^3+6x^2+8x+48

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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\[x^3+6x^2+8x+48=x^2(x+6)+8(x+6)=(x^2+8)(x+6)\]
do you get it?
no not really can u help me?

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Other answers:

ok in the first two term i took x^2 common, in the next two terms i took 8 common.. Do you get that part?
yes
ok in the thrid part i take (x+6) common.. so that is how i get that product
but where do u get (x-6) from?
it is x+6
i took it common no.. see the first two terms are\[x^3+6x^2\] so taking x^2 common i have\[x^2(x+6)\]
you get it?
yes i do now
so is the entire question clear or are u still unclear in some part?
no i get it now thanks
ok happy that you get it =D
okay wait one more question so how did u end up with (x^2+8)(x+6)

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