• anonymous
How do I sole ln(x^(2) - x - 2) = 2 + ln(x+1) This is as far as I have gotten ln((x^(2) - x - 2)/(x+1)) = 2 (x^(2) - x - 2)/(x+1) = e^(2) then I divided because I was too lazy to do algebra (x+1)(x-2) = e^(2) = x^(2)-x-2-e^(2) = 0 I'm not allowed to use a calculator I was thinking I could just sub these numbers into the quadratic formula to come up with solutions would that be the right course of action?
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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