anonymous
  • anonymous
What are the polar coordinates for the point (1,-2) i got r = 5 but theta = arctan -2?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\[r=\sqrt{5}\]
anonymous
  • anonymous
yeah i got that far
anonymous
  • anonymous
and yes, in this case \[\theta =\tan^{-1}(-2)\] because you are in quadrant 4

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anonymous
  • anonymous
okay so arctan(-2) is correct?
anonymous
  • anonymous
yes. it is always the case that \[\tan(\theta)=\frac{b}{a}\] but it is not always the case that \[\theta=\tan^{-1}(\frac{b}{a})\]
anonymous
  • anonymous
because arctan only returns answers in \[[-\frac{\pi}{2},\frac{\pi}{2}]\]so you need to be careful about what quadrant you are in

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