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anonymous
 5 years ago
Solve. 2x2 + 20x = –38
a. –5 ± √14
b. –5 ± √51
c. –5 ± √6
d. –5 ± √13
anonymous
 5 years ago
Solve. 2x2 + 20x = –38 a. –5 ± √14 b. –5 ± √51 c. –5 ± √6 d. –5 ± √13

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0c as usual. why is it always c?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can u show me how, though, im trying hard to remember but its not coming to me...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok first off each term has a factor of 2, so we can make our life easier by writing \[x^2+10x=19\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then we can write the left hand side as a perfect square , by taking half of 10, which is 5, squaring and adding it to both sides to get \[(x+5)^2=19+25=6\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then take the square root, don't forget the plus and minus \[x+5=\pm\sqrt{6}\] then subtract 5 \[x=5\pm\sqrt{6}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh i get it now, and this is for all problems like this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes you can always use this method. if you like you could write \[x^2+10x+19=0\] and then use the quadratic formula, but that would be more work because you would have a denominator, and then you would have to simplify the radical, factor and cancel to get the answer you see above

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh okay, thanks. can u also help me with http://openstudy.com/study?F295750376716BE3I5S=_#/updates/4f178119e4b0aeb795f57dc2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if the coefficient of the "middle term" is even, then it is much easier to complete the square
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