anonymous
  • anonymous
What value is added to both sides of the equation x2 – 8x = –10 in order to solve by completing the square? a. –8 b. 16 c. –4 d. 4 I think its a, am i right?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Mertsj
  • Mertsj
One half of 8 is 4 and 4 squared is 16 so add 16 to both sides.
anonymous
  • anonymous
wait what
anonymous
  • anonymous
what mertsj said, with exactly that reasoning

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
forget the number on the right hand side, it is irrelevant
anonymous
  • anonymous
you have \[x^2-\color{red}{8}x\] \[\frac{8}{2}=4, 4^2=16\] add 16 to both sides get \[(x-4)^2=-10+16=6\]
anonymous
  • anonymous
you should think it in english exactly as mertsj wrote it half of 8 is 4, 4 squared is 16
anonymous
  • anonymous
oh i see, i guess i understand better with visual. Thanks a ton!
anonymous
  • anonymous
\[x^2+12x=-5\] half of 12 is 6, 6 squared is 36 \[(x+6)^2=-5+36\] etc

Looking for something else?

Not the answer you are looking for? Search for more explanations.