What value is added to both sides of the equation x2 – 8x = –10 in order to solve by completing the square? a. –8 b. 16 c. –4 d. 4 I think its a, am i right?

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What value is added to both sides of the equation x2 – 8x = –10 in order to solve by completing the square? a. –8 b. 16 c. –4 d. 4 I think its a, am i right?

Mathematics
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One half of 8 is 4 and 4 squared is 16 so add 16 to both sides.
wait what
what mertsj said, with exactly that reasoning

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forget the number on the right hand side, it is irrelevant
you have \[x^2-\color{red}{8}x\] \[\frac{8}{2}=4, 4^2=16\] add 16 to both sides get \[(x-4)^2=-10+16=6\]
you should think it in english exactly as mertsj wrote it half of 8 is 4, 4 squared is 16
oh i see, i guess i understand better with visual. Thanks a ton!
\[x^2+12x=-5\] half of 12 is 6, 6 squared is 36 \[(x+6)^2=-5+36\] etc

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