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anonymous
 5 years ago
Help!!! Decompose into partial fractions. (x^43x^33x^2+10)/(x+1)^2(x3)
anonymous
 5 years ago
Help!!! Decompose into partial fractions. (x^43x^33x^2+10)/(x+1)^2(x3)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0really? this is a large pain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you need all the work, or just the answer? because it is annoying as hell

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can help. I have it all except for a few parts. let me post it h/o

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first you have to divide

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because degree of numerator is bigger than degree of denominator, so that is step one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[(x2)(7x+4/(x+1)^2(x3)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im not getting the next step right.. I get \[Ax^2+2Ax+A+Bx^3Bx^25Bx3B+Cx3x=x^3x^25x3\] This is from A/(x3)+B/(x+1)+C(x+1)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so we have \[x2\] we can ignore, and now you have \[\frac{7x4}{(x+1)^2(x3)}\] i will take your word for it. i know the \[x2\] is right now you need \[\frac{7x}{(x+1)^2(x3)}=\frac{a}{x1}+\frac{b}{(x1)^2}+\frac{c}{x3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i will use your notation \[\frac{7x}{(x+1)^2(x3)}=\frac{a}{x3}+\frac{b}{x1}+\frac{c}{(x1)^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[7x4=a(x1)^2+b(x3)(x1)+c(x3)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i would not use the "equate like coefficients" method yet. i would find a right away, but letting x = 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its "(x+1)" and "(x+1)^2" I believe, not "(x1)"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it is... \[7x4=a(x+1)^2+b(x3)(x+1)+c(x3)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i still let x = 3, get \[214=16a\] \[a=\frac{25}{16}\] but that is wrong, so maybe the 7x4 is wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im almost positive I got 7x+4 for the remainder when I divided earlier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok good, so we get \[7x+4=a(x+1)^2+b(x3)(x+1)+c(x3)\] \[x=3\] \[21+4=16a\] \[a=\frac{17}{16}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah ok, you had a minus sign in front of the whole thing and i didn't check it, but you are right , it is 7x+4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yup, you did it all right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you had a minus and then parentheses so i thought you meant minus the whole thing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now maybe let \[x=1\] and find c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohhh, my fault. The 17/16 is right for sure

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh yeah, i have the answer for sure \ http://www.wolframalpha.com/input/?i=partial+fractions+%28x^43x^33x^2%2B10%29%2F%28%28x%2B1%29^2%28x3%29%29

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i was just trying to get to it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can also use the "equate like coefficients" method but it requires solving a 3 by 3 system. i think substitution is much easier usually

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for example, if i replace x by 1 i get \[c=\frac{11}{4}\] pretty much in my head \[7+4=4c\] \[c=\frac{11}{4}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now that you have two out of the three the third one should be easy enough to find. plug in the numbers and see what is missing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This really helped a lot.. I know it involved a lot so thanks a bunch:)
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