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anonymous

  • 5 years ago

Can someone please explain me how to inverse a matrix?

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  1. anonymous
    • 5 years ago
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    Comin up......

  2. anonymous
    • 5 years ago
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    |dw:1326942286656:dw|

  3. anonymous
    • 5 years ago
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    There is a systematic way to find the inverse of a matrix that isn't so difficult. It might take a bit to type up, so bear with me!

  4. anonymous
    • 5 years ago
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    LOL Thanks :D My book doesn't show how it got it so I am just wondering how

  5. anonymous
    • 5 years ago
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    I think u gotta use G-J elimination

  6. anonymous
    • 5 years ago
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    i think you need the determinant with it also

  7. anonymous
    • 5 years ago
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    but only if it is 2by 2 matrix no?

  8. anonymous
    • 5 years ago
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    First, you create a 3 x 6 matrix, like so: \[\begin{matrix} 2 & 3 & 1 & 1 & 0 & 0 \\ 3 & 3 & 1 & 0 & 1 & 0 \\ 2 & 4 & 1 & 0 & 0 & 1 \end{matrix}\] Then, you use GJ elimination methods until you have \[\begin{matrix} 1 & 0 & 0 & a & b &c \\ 0 & 1 & 0 & d &e & f \\ 0 & 0 & 1 & g & h & i \end{matrix}\] Take that 3x3 matrix on the right, multiply it by 1 over the determinant of your original matrix, and you are done!

  9. anonymous
    • 5 years ago
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    Are u sure you have to use the determinant can u just use elimination?

  10. anonymous
    • 5 years ago
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    cuz we didnt learn abt that yet really

  11. anonymous
    • 5 years ago
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    Only in next chapter

  12. anonymous
    • 5 years ago
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    Sorry, you don't need to divide by the determinant, my bad.

  13. anonymous
    • 5 years ago
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    lol Thnx

  14. anonymous
    • 5 years ago
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    That was helpful :D

  15. anonymous
    • 5 years ago
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    No problem! :) Also, this method is how you find the inverses of matrices in general. You'll note that if you try to solve the standard 2x2 matrix with this method, you will get the inverse that you probably learned in class. There are some slightly easier techniques to solve 3x3 matrices, but the proof of the validity of that method requires some linear algebra. Besides, this method always works!

  16. anonymous
    • 5 years ago
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    Thanks

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