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anonymous

  • 5 years ago

someone take a look at this please lim_{x rightarrow -1} (x^2 - 7x + 8/ x - 5)^2

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  1. anonymous
    • 5 years ago
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    \[\lim_{x \rightarrow -1} (x^2 - 7x + 8/ x - 5)^2\]

  2. myininaya
    • 5 years ago
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    plug in -1 since the function is continuous at -1

  3. anonymous
    • 5 years ago
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    i tried that and i dont know what im doing wrong but my software wont accept the result

  4. myininaya
    • 5 years ago
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    \[\frac{(-1)^2-7(-1)+8}{(-1-5)^2}\] is that right?

  5. myininaya
    • 5 years ago
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    or is the square on the whole thing?

  6. anonymous
    • 5 years ago
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    what happens to the exponent outside the paranthesis

  7. myininaya
    • 5 years ago
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    could you answer my question first? is the square on the whole thing or just the bottom?

  8. anonymous
    • 5 years ago
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    the whole thing

  9. myininaya
    • 5 years ago
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    \[(\frac{(-1)^2-7(-1)+8}{(-1-5)})^2\]

  10. myininaya
    • 5 years ago
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    so perform what is inside first

  11. myininaya
    • 5 years ago
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    \[(\frac{1+7+8}{-6})^2=(\frac{16}{-6})^2=(\frac{-8}{3})^2=\frac{64}{9}\]

  12. anonymous
    • 5 years ago
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    i see. thank you very much. i have alot of similar problems like this. would you be willing to work with me please?

  13. myininaya
    • 5 years ago
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    just post the questions as a new thread and i will work a little longer tonight but not much more

  14. anonymous
    • 5 years ago
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    ok thanks

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spraguer (Moderator)
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