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anonymous
 4 years ago
Help!! Im a little stuck.. I need to decompose this into partial fractions:
anonymous
 4 years ago
Help!! Im a little stuck.. I need to decompose this into partial fractions:

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(2x^211x+5)/(x3)(x^2+x4)\]

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1What course are you currently taking?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This is PreCalc Hero

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Then I use A/(x3)+B(x^2+x4)

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1What textbook are you using for the course?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Precalculus: Graphs and Models by Addison Wesley

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1That's okay. Sometimes, old is better.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Okay. I mean its probably all the same techniques, for the most part.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1Well, nevermind. I'll get get the latest edition.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok I wasnt sure. I dont know if it says it for sure.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1If you have the book, it will say what edition it is. You just have to look, but okay.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1I have about 9 min left before it finishes downloading

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I really dont see it at all :O This is the exact book though http://www.abebooks.com/booksearch/isbn/0201694425/hardcover/

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok thats fine. Thanks

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1If you want to show someone a book, use amazon.com

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1Yes, that version is very old. It's not even available for download. It's the first edition apparently

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1If you have the book, is there any reason why you are not able to understand this concept?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I get the concepts down sort of, I just end up with the wrong numbers. I either do a step too early or Im not doing it completely right. I just want to make sure I understand it

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1Okay, I will have a look here in about 15 secs

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok Ill go through with what Im doing and you can maybe see what Im doing wrong

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Let me know when its done

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1It might take me a bit to figure this out.

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1Okay, I see something similar to this where it talks about setting up a decomposition template.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Its in a lesson called Partial Fractions in my book

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That sounds right though

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{2x^2  11x+5}{(x3)(x^2+x4)} = \frac{A}{x3} + \frac{Bx + C}{x^2 + x 4}\]

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1Maybe that's what you're looking for.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So then its \[A(x^2+x4)+(x3)(Bx+C)=2x^211x+5\]

Hero
 4 years ago
Best ResponseYou've already chosen the best response.1What I posted is in your book so it is correct. If what you posted is the next step, then by all means, go right ahead, but maybe someone else can take a look at that for you.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok thats cool. I needed that for sure so thanks a lot Hero
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