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anonymous
 4 years ago
Solve the equation for 0≤x<2π
» 2sin²2x=1
anonymous
 4 years ago
Solve the equation for 0≤x<2π » 2sin²2x=1

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vishal_kothari
 4 years ago
Best ResponseYou've already chosen the best response.92sin²2x = 1 divide both sides by 2 sin²2x = 1/2 take the sq roots of both the sides sin2x = 1/√2 or sin2x = 1/√2 Take the inverse sine of both sides: 2x = π/4 or sin2x = 1/√2 divide both sides by 2 x = π/8 or sin2x = 1/√2 take the inverse of sine of both sides x = π/8 or 2x = π/4 divide both sides by 2 x = π/8 or x = π/8...
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