anonymous
  • anonymous
how many grams of CaCl2 must dissolve to release 192 KJ of heat? answer is 258 g but i need to know the process! help please! quiz tomorow!
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[CaCl _{2}\rightarrow Ca _{aq.}+2Cl _{aq.} ; DeltaHsoln=-82.8kj/mol\]
anonymous
  • anonymous
equation was given with problem
anonymous
  • anonymous
ok using you balanced thermo equation we can pull out the conversion factor 1mole cacl2=82.8 kj Now we factor lable this bad boy, \[192 kj (\frac{1 mol CaCl_2}{82.8 kj})(\frac{111 g CaCl_2}{1 mole CaCl_2})=\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
im sorry im still kinda lost what do you do after its set up like that?
anonymous
  • anonymous
take 192 multiply it to the top of the fraction then divide it by the bottom of the raction till you get to the end and you will have your answer.
anonymous
  • anonymous
okay i understand a bit better and the 111 came from the table of elements added up ca and cl2 right?
anonymous
  • anonymous
Yea but i'm guessing there is a difference between the table i use compaired to the one the answer came from or a rounding error or something because I got 257.39 kj i think it was. This also could be a case were carring numbers gives us a slightly different answer. However thats how it should be set up you can look at the molar mass and see if its the same or slightly different off your peroidic table.
anonymous
  • anonymous
yea i got it thanks!
anonymous
  • anonymous
No problem good luck on your quiz tomorrow
anonymous
  • anonymous
yea lol im going to need it do you think you can help me with one more?
anonymous
  • anonymous
I can try
anonymous
  • anonymous
thanks sorry for the wait its the same eq. but its asking for heat released if you prepeare 2.75L of 1.75 M [CaCl2 solution
anonymous
  • anonymous
and the answer was 285 Kj
anonymous
  • anonymous
\[2.75 L (\frac{1.75 mol}{1 L})(\frac{82.8 kj}{1 mole})=\] It should look something like that but this one isn't working out and i'm getting tired. Is there anything that you left out in the question?
anonymous
  • anonymous
no thats all there was in the question, and thanks for trying lol ill ask a classmate tomorrow morning lol i still have to study for my math and physics test too so i cant put to much time on thsi but thanks for the help i appreciate it :)
anonymous
  • anonymous
np and sorry i couldn't figure out this last one
anonymous
  • anonymous
thats okay, lucky for me i know all the smarties in the class so they will help me out so not to worry besides i have an hour in the morining to figure this out before i get to school so np :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.