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moongazer
 4 years ago
I. Find the solutions of the following trigonometric conditional equations for 0 ≤ ϴ ≤ 2π. (Rx2)
1. 4 cos ϴ + 4 = 0
2. sec 2 ϴ = 1
3. sin ϴ  1 = 0
4. 2 cos ϴ  1 = 0
5. 4 cos2 ϴ = 3
6. cos ϴ + sin 2ϴ = 0
7. cot 2ϴ = 3
8. cos2 ϴ  cos ϴ = 0
9. sin2 ϴ = ¾
10. csc2 ϴ  1 = 0
moongazer
 4 years ago
I. Find the solutions of the following trigonometric conditional equations for 0 ≤ ϴ ≤ 2π. (Rx2) 1. 4 cos ϴ + 4 = 0 2. sec 2 ϴ = 1 3. sin ϴ  1 = 0 4. 2 cos ϴ  1 = 0 5. 4 cos2 ϴ = 3 6. cos ϴ + sin 2ϴ = 0 7. cot 2ϴ = 3 8. cos2 ϴ  cos ϴ = 0 9. sin2 ϴ = ¾ 10. csc2 ϴ  1 = 0

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moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0I don't know how to solve the parts with sec 2 ϴ = 1,sec 2 ϴ = 1, csc2 ϴ  1 = 0 I don't know if it is a typo or it is the real equation.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is it sec^2 or sec(2x) ?

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0is it possible to solve if it is sec(2x) ????

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0because I think it is typo

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes sec(2x) = 1 1/cos(2x) =1 cos(2x) = 1 cos is 1 when angle is 0 2x = 0 x = 0

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0thanks! I'll just try both

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if its squared, then it will be sec(x) = +1

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0w8 I think your solution is incomplete

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh, you are right 2x =2pi x = pi

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0isn't it that sec 2A will be 1/(cos^2 A  sin^2 A) ??????????

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0My teacher taught us that cos2A = cos^2 A  sin^2 A

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry, cos^2  sin^2 = 1 cos^2 = 1+ sin^2 cos^2 = 1+(1cos^2) 2cos^2 = 2 cos^2 = 1 cos A = +1 so you end up with same solutions A = 0,pi

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sure, the csc one will work the same way

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.0another thing is 1/x = 1 also the same as x=1 ??? because when you cross multiply it, it will be the result?
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