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anonymous

  • 5 years ago

(please show steps) solve the inequality: 1/x <(or equal to) 1/x+1

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  1. anonymous
    • 5 years ago
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    OK, well, how do you solve an equation with a variable in the denominator?

  2. anonymous
    • 5 years ago
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    muahah. yay. actual not answering.

  3. anonymous
    • 5 years ago
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    \[1/x \le 1/x+1\]times all terms by x \[1 \le 1+x\]solve for x \[0 \le x\]\[x \ge 0\]

  4. anonymous
    • 5 years ago
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    is that a 1/x +1 or a 1/(x+1) ?

  5. anonymous
    • 5 years ago
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    (x+1)

  6. anonymous
    • 5 years ago
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    1/x-1/(x+1)<0 taking LCM you get 1/(x(x+1))<0 , This means -1<=x<=0

  7. anonymous
    • 5 years ago
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    Remember never cancel x on both sides of the inequality even if you get it common, take it the other side and factorize. (If x is negative the inequality is reversed on cancelling x n both sides)

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