## anonymous 5 years ago The half life of radon is 3.80 days what would be its decay constant?

Hi! Hope you will be fine :D Half life formula is, $0.5=e ^{k*t}$ where, k=decay constant t=time substitute time, we get $0.5=e ^{k*3.80}$ taking natural logarithm on both sides, we get, $\ln(0.5)=k*3.80$ or, $\ln(0.5)/3.80=k$ $k=0.182$(ANSWER) Regards, Electronics engineer. *but I ain't good in nuclear physics :D