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moongazer
 5 years ago
4 cos2 ϴ = 3 find ϴ?
moongazer
 5 years ago
4 cos2 ϴ = 3 find ϴ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[4cos(2ϴ)=3\]\[cos(2ϴ)=\frac{3}{4}\]\[2ϴ=2n\pi+cos^{1}(\frac{3}{4})\]\[ϴ=n\pi+\frac{1}{2}cos^{1}(\frac{3}{4})\] where n is an integer

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1OR cos(2x) = 3/4 cos^2  sin^2 = 3/4 cos^2 (1cos^2) = 3/4 2cos^2 1 = 3/4 2cos^2 = 7/4 cos^2 = 7/8 cos(x) = +sqrt(7)/2sqrt2

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.1its more likely cos^2 rather than cos(2x) in this case >cos^2 = 3/4 cos(x) = +sqrt3/2 x = pi/6, 5pi/6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think you're right @dumbcow i didn't even think about the cos^2 :)
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