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anonymous

  • 5 years ago

Is this differential equation homogeneuos? F(x,y,y',y'')=0 And how would look like nonhomogeneuos DE in this form?

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  1. anonymous
    • 5 years ago
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    Yes, a homogenous equation is equal to 0

  2. anonymous
    • 5 years ago
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    and how would look like nonhomogeneuos?

  3. anonymous
    • 5 years ago
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    a non-homogenous equation would equal some function of x or a constant

  4. anonymous
    • 5 years ago
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    Ehhhh I'd be careful with this... F(x,y,y',y'') = y'' + y' + y + sin(x) = 0 is not homogeneous...

  5. anonymous
    • 5 years ago
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    i know, but im interesting in this form....F(x,y',y'',..)=0....you have x here,maybe this is a constant?

  6. anonymous
    • 5 years ago
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    ahh good point Jemurray3 i missed the x in there.

  7. anonymous
    • 5 years ago
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    http://www.dummies.com/how-to/content/defining-homogeneous-and-nonhomogeneous-differenti.html

  8. anonymous
    • 5 years ago
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    so, from this for you can only see its second order?

  9. anonymous
    • 5 years ago
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    The definition for a homogeneous second order differential that I always would fall back on is something of the form \[ a(x) y''(x) + b(x) y'(x) + c(x) y(x) = 0\]

  10. anonymous
    • 5 years ago
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    differential equation*

  11. anonymous
    • 5 years ago
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    Just so long as every term involves y or one of its derivatives, really.

  12. anonymous
    • 5 years ago
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    but from this form you cant conclude if its homogeneuos or not?

  13. anonymous
    • 5 years ago
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    F(x,y,y',y'') = 0 defines a second order, ordinary differential equation. That is all the information you can get from that.

  14. anonymous
    • 5 years ago
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    ok, thanks

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