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moongazer

  • 5 years ago

Determine the equivalent slope of the line based on the given conditions. 1. through points (-4, 8) and (2, -3) is it 11?

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  1. anonymous
    • 5 years ago
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    \[m=\frac{y_2-y_1}{x_2-x_1}\]\[m=\frac{-3-8}{2+4}\]\[m=\frac{-11}{6}\]

  2. moongazer
    • 5 years ago
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    if not how do you find it also for whose equation is 3x – 4y = 12. whose equation is y = -3.

  3. moongazer
    • 5 years ago
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    Thanks! I forgot that the formula for slope is that. :)

  4. anonymous
    • 5 years ago
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    for 3x-4y=12 we need to write it in the form y=mx+c 3x-4y=12 -4y=12-3x y=-3+3/4x So the gradient m=3/4

  5. moongazer
    • 5 years ago
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    What is gradient?

  6. anonymous
    • 5 years ago
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    the slope

  7. moongazer
    • 5 years ago
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    other term for slope is gradient?

  8. anonymous
    • 5 years ago
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    correct

  9. moongazer
    • 5 years ago
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    Thanks for that information. :)

  10. anonymous
    • 5 years ago
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    For y=-3 use the formula of the slope again m=(y2-y1)/(x2-x1) =(-3+3)/(2-1) =0/1 =0

  11. anonymous
    • 5 years ago
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    we know that for y=-3 at any x value y=-3

  12. moongazer
    • 5 years ago
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    Can we just consider that m=0 in "For y=-3" that "m=0" because there is no x and that means that it is y=0x-3 sorry for my bad grammar.

  13. anonymous
    • 5 years ago
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    yes that's another way to do it, :D

  14. moongazer
    • 5 years ago
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    how about this? parallel to the line whose equation is x = 2.

  15. anonymous
    • 5 years ago
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    Because x=2 has a undetermined (m=some number/0) slope a parallel line would be x=3 or x=4 or x= any number

  16. moongazer
    • 5 years ago
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    Sorry but I don't get it. :)

  17. moongazer
    • 5 years ago
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    could explain it further?

  18. anonymous
    • 5 years ago
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    we can write x=2 as y*0=x-2 okay?

  19. moongazer
    • 5 years ago
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    I think I slightly got your explanation when I imagined a graph.

  20. moongazer
    • 5 years ago
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    anyway.. please continue to your explanation. :)

  21. anonymous
    • 5 years ago
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    and rewriting it in the form y=mx+c we get y=x/0-2/0 but x/0 is undefined so we need to find an equation that has an undefined slope. y=ax/0+c/0 where a and c are constants

  22. anonymous
    • 5 years ago
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    so y=ax/0+c/0 y=(ax+c)/0 y*0=(ax+c) ax+c=0 ax=-c x=-c/a

  23. anonymous
    • 5 years ago
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    does this make more sense?

  24. moongazer
    • 5 years ago
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    i'll just analyze it wait for a while. :)

  25. moongazer
    • 5 years ago
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    I didn't get it.

  26. moongazer
    • 5 years ago
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    could you graph it?? and btw what is the answer again. I might get it if I know the answer.

  27. anonymous
    • 5 years ago
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    |dw:1326969920159:dw| The answer is x=-c/a where c is any value and a can be any number but 0 So in the graph we have x=2, a line parallel to it is x=-3 and so is x=-1, x=9, x=11, ...., x=anynumber

  28. moongazer
    • 5 years ago
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    now I get it.

  29. moongazer
    • 5 years ago
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    so my answer will be "m is any real number but not zero" ???

  30. anonymous
    • 5 years ago
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    Is it x=m? In which case it can be any number even 0

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