moongazer
  • moongazer
Determine the equivalent slope of the line based on the given conditions. 1. through points (-4, 8) and (2, -3) is it 11?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[m=\frac{y_2-y_1}{x_2-x_1}\]\[m=\frac{-3-8}{2+4}\]\[m=\frac{-11}{6}\]
moongazer
  • moongazer
if not how do you find it also for whose equation is 3x – 4y = 12. whose equation is y = -3.
moongazer
  • moongazer
Thanks! I forgot that the formula for slope is that. :)

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More answers

anonymous
  • anonymous
for 3x-4y=12 we need to write it in the form y=mx+c 3x-4y=12 -4y=12-3x y=-3+3/4x So the gradient m=3/4
moongazer
  • moongazer
What is gradient?
anonymous
  • anonymous
the slope
moongazer
  • moongazer
other term for slope is gradient?
anonymous
  • anonymous
correct
moongazer
  • moongazer
Thanks for that information. :)
anonymous
  • anonymous
For y=-3 use the formula of the slope again m=(y2-y1)/(x2-x1) =(-3+3)/(2-1) =0/1 =0
anonymous
  • anonymous
we know that for y=-3 at any x value y=-3
moongazer
  • moongazer
Can we just consider that m=0 in "For y=-3" that "m=0" because there is no x and that means that it is y=0x-3 sorry for my bad grammar.
anonymous
  • anonymous
yes that's another way to do it, :D
moongazer
  • moongazer
how about this? parallel to the line whose equation is x = 2.
anonymous
  • anonymous
Because x=2 has a undetermined (m=some number/0) slope a parallel line would be x=3 or x=4 or x= any number
moongazer
  • moongazer
Sorry but I don't get it. :)
moongazer
  • moongazer
could explain it further?
anonymous
  • anonymous
we can write x=2 as y*0=x-2 okay?
moongazer
  • moongazer
I think I slightly got your explanation when I imagined a graph.
moongazer
  • moongazer
anyway.. please continue to your explanation. :)
anonymous
  • anonymous
and rewriting it in the form y=mx+c we get y=x/0-2/0 but x/0 is undefined so we need to find an equation that has an undefined slope. y=ax/0+c/0 where a and c are constants
anonymous
  • anonymous
so y=ax/0+c/0 y=(ax+c)/0 y*0=(ax+c) ax+c=0 ax=-c x=-c/a
anonymous
  • anonymous
does this make more sense?
moongazer
  • moongazer
i'll just analyze it wait for a while. :)
moongazer
  • moongazer
I didn't get it.
moongazer
  • moongazer
could you graph it?? and btw what is the answer again. I might get it if I know the answer.
anonymous
  • anonymous
|dw:1326969920159:dw| The answer is x=-c/a where c is any value and a can be any number but 0 So in the graph we have x=2, a line parallel to it is x=-3 and so is x=-1, x=9, x=11, ...., x=anynumber
moongazer
  • moongazer
now I get it.
moongazer
  • moongazer
so my answer will be "m is any real number but not zero" ???
anonymous
  • anonymous
Is it x=m? In which case it can be any number even 0

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