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\[m=\frac{y_2-y_1}{x_2-x_1}\]\[m=\frac{-3-8}{2+4}\]\[m=\frac{-11}{6}\]

if not how do you find it
also for
whose equation is 3x – 4y = 12.
whose equation is y = -3.

Thanks! I forgot that the formula for slope is that. :)

What is gradient?

the slope

other term for slope is gradient?

correct

Thanks for that information. :)

For y=-3
use the formula of the slope again
m=(y2-y1)/(x2-x1)
=(-3+3)/(2-1)
=0/1
=0

we know that for y=-3 at any x value y=-3

yes that's another way to do it, :D

how about this? parallel to the line whose equation is x = 2.

Sorry but I don't get it. :)

could explain it further?

we can write x=2 as y*0=x-2 okay?

I think I slightly got your explanation when I imagined a graph.

anyway.. please continue to your explanation. :)

so y=ax/0+c/0
y=(ax+c)/0
y*0=(ax+c)
ax+c=0
ax=-c
x=-c/a

does this make more sense?

i'll just analyze it wait for a while. :)

I didn't get it.

could you graph it?? and btw what is the answer again. I might get it if I know the answer.

now I get it.

so my answer will be "m is any real number but not zero" ???

Is it x=m? In which case it can be any number even 0