A community for students.
Here's the question you clicked on:
 0 viewing
moongazer
 4 years ago
The distance of point (1, 4) and the line 4x – 2y = 4 is ___.
moongazer
 4 years ago
The distance of point (1, 4) and the line 4x – 2y = 4 is ___.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.04x2y4=0 put the values of x and y in the LHS then take the modulus of that value and divide it by sqrt of sum of the squares of coeffients of x and y. i think, u know the proof why we do that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry, coefficients ^^

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.1Sorry but I didn't get it.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2since the distance from a point to a line is along a perpendiular line; if we can construct a perpendicular line equation that goes thru the given point we can use a system of equations to determine the point where they meet. then use the distance formula to determine the distance from the meeting point and the given point.

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2dw:1326977726363:dw

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2one trick to a perp line is to swap coeffs and negate one of them: 4x – 2y = 4 perp line: 2x + 4y = n calibrate with the given point (1,4): 2(1) + 4(4) = n 2 + 16 = n = 14 perp line: 2x + 4y = 14

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2system of equations gives us: 4x  2y = 4 2x + 4y = 14 ; *2 4x  2y = 4 4x 8y = 28  10y = 24 y = 24/10 = 12/5 .............................................. 4x  2y = 4 ;*2 2x + 4y = 14 8x  4y = 8 2x + 4y = 14  10x = 22 x = 22/10 = 11/5 ................................ we want the distance from (1,4) to (12/5, 11/5) if i did that right

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.1I think this is the explanation that I am looking for.

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.1could I use the formula d=(/Ax1+By1+C/)/sqrtof(a^2+B^2) I think this is the formula for this. :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2\[dist.=\sqrt{a^2+b^2}\] is a compact form of the distance formula yes; personally I just subtract the points, square them, add them and sqrt them

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2( 12/5, 11/5)  ( 5/5, 20/5)  (17/5 , 9/5) ^2 (289+81)/25 sqrt(370)/5

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2that should simplify to 8/sqrt(5)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2but then some texts hate a sqrt in the denom; so maybe we rewrite it: \(cfrac{8}{5}\sqrt{5}\)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2well that dint format good on my screen lol

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2\[\frac{8\sqrt{5}}{5}\] or \[\frac{8}{5}\sqrt{5}\]

moongazer
 4 years ago
Best ResponseYou've already chosen the best response.1\[ d= (\left Ax _{1}+Bx _{2}+C \right)/\sqrt{A ^{2}+B ^{2}}\] This is what my teacher taught us :)

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.2that might work :) ive never quite seen it like that tho.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.