A cork of density 0.15 g/cm^3 floats in a bucket of water with 10 cm^3 of its volume above the surface of water.Find the mass of the cork.

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

A cork of density 0.15 g/cm^3 floats in a bucket of water with 10 cm^3 of its volume above the surface of water.Find the mass of the cork.

Physics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

do u know how to do this?
\[d=\frac{m}{V}\] Therefore, \[m=dV\] Hope this helps, somehow. I'm unsure.
how?can u solve it?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

help tomas......
i think you need to use Archimedus law or something
|dw:1326975917374:dw|
|dw:1326976017906:dw|
ya so now?
also \[F_a>mg\] if that matters lol
i know but then i am stuck at hw to find the missin volume..............
hi
u hv the same problem?
i posted fr u
nanbenda
jacob help man!
wait sachin
I think you have to use Archimedes Principle and Density- Mass relationship. Still I am not getting the equation.
i know but how????
how is d=m/g
Sorry, i was saying whether we can use density = mass/volume?
yeah we can use anythin
Then it is simple. Mass= volume X density, so Mass= 10 * 0.15= 1.5 gm (Still u check the answer)
AADARSH!did u see my diagram and read the question again ....
answer is wrong
Saw it, but confused about the equation
volume is 10+some x
I will consult and say u tomorrow
\[\rho=0.15\,g/cm^3\quad,\quad \rho_w=1\,g/cm^3\quad,\quad V\uparrow=10\,cm^3\]\[\rho Vg=\rho_w V\downarrow g\quad\Rightarrow\quad \frac{V}{V\downarrow}=\frac{V\uparrow+V\downarrow}{V\downarrow}=\frac{V\uparrow}{V\downarrow}+1=\frac{\rho_w}{\rho}\]\[V\downarrow=\frac{\rho}{\rho_w-\rho}V\uparrow\]\[m=\rho(V\uparrow+V\downarrow)=\rho\left(1+\frac{\rho}{\rho_w-\rho}\right)V\uparrow=\frac{\rho\rho_w}{\rho_w-\rho}V\uparrow\]\[m=\frac{0.15}{0.85}\cdot 10\,g=1.765\,g\]
nikvist, this a good answer. I understand your notation. But perhaps for the others could you explain in words what you've done here? Thanks.
|dw:1326987424332:dw|For practical purposes water is incompressible so the submerged part would displace an amount of water equal to its own volume. so same mass that is what nikivist has done ...equate the mass of cork as a whole to mass of water displaced then manipulations gives us everything written in terms of density which we know(data in the question)
nikvist could u explain ure answer in words or JamesJ could u do it fr him?
hmmm..... that is wat i did.............
Please explain in simple words. Are we to use that Density formula or not?
I WILL TELL EVERYTHING FROM FIRST by archimedes principle, the wt of cork=wt of water displaced(buoyant force) this is because the body is floating upward forces=downward then wt of cork=volume*density*g wt of water displaced=volume(V)*density oif water*g write volume of cork as volume of upper immersed portion+vol of downward immersed portion(V) REMEMBER IT IS V that we need to calculate do it in simple terms after this |dw:1327073074048:dw|
knowingV it is easy to calculate the mass of that part of cork+mass of upper part of cork...........got it adarsh?
Yeah
u need to know here that by archimedes principle,buoyant force=wt of water displaced in this case as the cork is floating the wt mg equals the buoyant force so to to keep the cork at rest
Yeah, that's right.
adarsh see this link for better understabding http://ocw.mit.edu/courses/physics/8-01-physics-i-classical-mechanics-fall-1999/video-lectures/lecture-28/
Seeing.
here is yours ans attachment below hope it will help you
1 Attachment

Not the answer you are looking for?

Search for more explanations.

Ask your own question