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King

A cork of density 0.15 g/cm^3 floats in a bucket of water with 10 cm^3 of its volume above the surface of water.Find the mass of the cork.

  • 2 years ago
  • 2 years ago

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  1. King
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    do u know how to do this?

    • 2 years ago
  2. Gab02282
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    \[d=\frac{m}{V}\] Therefore, \[m=dV\] Hope this helps, somehow. I'm unsure.

    • 2 years ago
  3. King
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    how?can u solve it?

    • 2 years ago
  4. King
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    help tomas......

    • 2 years ago
  5. Tomas.A
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    i think you need to use Archimedus law or something

    • 2 years ago
  6. King
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    |dw:1326975917374:dw|

    • 2 years ago
  7. Tomas.A
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    |dw:1326976017906:dw|

    • 2 years ago
  8. King
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    ya so now?

    • 2 years ago
  9. Tomas.A
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    also \[F_a>mg\] if that matters lol

    • 2 years ago
  10. King
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    i know but then i am stuck at hw to find the missin volume..............

    • 2 years ago
  11. sachin_vishaul
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    hi

    • 2 years ago
  12. sachin_vishaul
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    u hv the same problem?

    • 2 years ago
  13. King
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    i posted fr u

    • 2 years ago
  14. sachin_vishaul
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    nanbenda

    • 2 years ago
  15. King
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    jacob help man!

    • 2 years ago
  16. King
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    wait sachin

    • 2 years ago
  17. Aadarsh
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    I think you have to use Archimedes Principle and Density- Mass relationship. Still I am not getting the equation.

    • 2 years ago
  18. King
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    i know but how????

    • 2 years ago
  19. King
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    how is d=m/g

    • 2 years ago
  20. Aadarsh
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    Sorry, i was saying whether we can use density = mass/volume?

    • 2 years ago
  21. King
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    yeah we can use anythin

    • 2 years ago
  22. Aadarsh
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    Then it is simple. Mass= volume X density, so Mass= 10 * 0.15= 1.5 gm (Still u check the answer)

    • 2 years ago
  23. King
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    AADARSH!did u see my diagram and read the question again ....

    • 2 years ago
  24. King
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    answer is wrong

    • 2 years ago
  25. Aadarsh
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    Saw it, but confused about the equation

    • 2 years ago
  26. King
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    volume is 10+some x

    • 2 years ago
  27. Aadarsh
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    I will consult and say u tomorrow

    • 2 years ago
  28. nikvist
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    \[\rho=0.15\,g/cm^3\quad,\quad \rho_w=1\,g/cm^3\quad,\quad V\uparrow=10\,cm^3\]\[\rho Vg=\rho_w V\downarrow g\quad\Rightarrow\quad \frac{V}{V\downarrow}=\frac{V\uparrow+V\downarrow}{V\downarrow}=\frac{V\uparrow}{V\downarrow}+1=\frac{\rho_w}{\rho}\]\[V\downarrow=\frac{\rho}{\rho_w-\rho}V\uparrow\]\[m=\rho(V\uparrow+V\downarrow)=\rho\left(1+\frac{\rho}{\rho_w-\rho}\right)V\uparrow=\frac{\rho\rho_w}{\rho_w-\rho}V\uparrow\]\[m=\frac{0.15}{0.85}\cdot 10\,g=1.765\,g\]

    • 2 years ago
  29. JamesJ
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    nikvist, this a good answer. I understand your notation. But perhaps for the others could you explain in words what you've done here? Thanks.

    • 2 years ago
  30. salini
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    |dw:1326987424332:dw|For practical purposes water is incompressible so the submerged part would displace an amount of water equal to its own volume. so same mass that is what nikivist has done ...equate the mass of cork as a whole to mass of water displaced then manipulations gives us everything written in terms of density which we know(data in the question)

    • 2 years ago
  31. King
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    nikvist could u explain ure answer in words or JamesJ could u do it fr him?

    • 2 years ago
  32. salini
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    hmmm..... that is wat i did.............

    • 2 years ago
  33. Aadarsh
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    Please explain in simple words. Are we to use that Density formula or not?

    • 2 years ago
  34. salini
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    I WILL TELL EVERYTHING FROM FIRST by archimedes principle, the wt of cork=wt of water displaced(buoyant force) this is because the body is floating upward forces=downward then wt of cork=volume*density*g wt of water displaced=volume(V)*density oif water*g write volume of cork as volume of upper immersed portion+vol of downward immersed portion(V) REMEMBER IT IS V that we need to calculate do it in simple terms after this |dw:1327073074048:dw|

    • 2 years ago
  35. salini
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    knowingV it is easy to calculate the mass of that part of cork+mass of upper part of cork...........got it adarsh?

    • 2 years ago
  36. Aadarsh
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    Yeah

    • 2 years ago
  37. salini
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    u need to know here that by archimedes principle,buoyant force=wt of water displaced in this case as the cork is floating the wt mg equals the buoyant force so to to keep the cork at rest

    • 2 years ago
  38. Aadarsh
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    Yeah, that's right.

    • 2 years ago
  39. salini
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    adarsh see this link for better understabding http://ocw.mit.edu/courses/physics/8-01-physics-i-classical-mechanics-fall-1999/video-lectures/lecture-28/

    • 2 years ago
  40. Aadarsh
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    Seeing.

    • 2 years ago
  41. unicorn
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    here is yours ans attachment below hope it will help you

    • 2 years ago
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