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anonymous
 5 years ago
(a 1 2)
(0 a 1)
(1 a 0)
That's a matrix. For what values of a is the matrix invertible?
anonymous
 5 years ago
(a 1 2) (0 a 1) (1 a 0) That's a matrix. For what values of a is the matrix invertible?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This matrix is invertible if and only if the determinate is equal to 0. det=a(a*01*a)0(1*02*a)+1(1*12*a) 0=a(a)0(2a)+1(12a) 0=a^2+12a 0=a^2+2a1 Using quadratic formula a=1sqrt(2) and a=1+sqrt(2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow. you are smart. thank you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait a second  isn't it the other way round? i.e. a matrix is invertible when the determinant is not zero.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You are correct, I read it wrong. So that means the matrix is invertible for all values except for the ones listed above. If there exists a matrix B such that \[AB=BA=I \] I was supposed to write This matrix is not invertible if and only if the determinate is equal to 0. Nice work :D
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