anonymous
  • anonymous
(a 1 2) (0 a 1) (1 a 0) That's a matrix. For what values of a is the matrix invertible?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
This matrix is invertible if and only if the determinate is equal to 0. det=a(a*0-1*a)-0(1*0-2*a)+1(1*1-2*a) 0=a(-a)-0(-2a)+1(1-2a) 0=-a^2+1-2a 0=a^2+2a-1 Using quadratic formula a=-1-sqrt(2) and a=-1+sqrt(2)
anonymous
  • anonymous
wow. you are smart. thank you
anonymous
  • anonymous
wait a second - isn't it the other way round? i.e. a matrix is invertible when the determinant is not zero.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
You are correct, I read it wrong. So that means the matrix is invertible for all values except for the ones listed above. If there exists a matrix B such that \[AB=BA=I \] I was supposed to write This matrix is not invertible if and only if the determinate is equal to 0. Nice work :D
anonymous
  • anonymous
thanks again
anonymous
  • anonymous
Thank you!

Looking for something else?

Not the answer you are looking for? Search for more explanations.