anonymous
  • anonymous
anti-derivative (1)/x^2dx
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
amistre64
  • amistre64
\[\int x^{-2}\ dx\]
amistre64
  • amistre64
to derive a power we multiply and subtract 1, to undo that we add 1 and divide
anonymous
  • anonymous
So would my answer be (-1/3x^3)?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
it would; +C
amistre64
  • amistre64
opps, read it wrong: -1/3 x^-3
amistre64
  • amistre64
+C ....
amistre64
  • amistre64
\[\int x^{-2}\ dx=-\frac{1}{1}x^{-1}=-\frac{1}{x}+C\] thats better
anonymous
  • anonymous
okay thanks. I need to know how to type another problem but I do not know how to type it in integral notation. COuld you explain how to do that please?
amistre64
  • amistre64
I gotta get to class at the moment; but good luck :)
anonymous
  • anonymous
ok well later Thanks. :)
anonymous
  • anonymous
use the power rule backwards
anonymous
  • anonymous
\[\frac{d}{dx}x^n=nx^{n-1}\] \[\int x^n dx=\frac{x^{n+1}}{n+1}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.