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anonymous
 5 years ago
tan∠A  csc∠C = 3x
anonymous
 5 years ago
tan∠A  csc∠C = 3x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How do you solve this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0At some point I got 3x sqrt74/5= 7/sqrt 74

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am confused because you have 3 variables, A, C and x. what are you trying to solve?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am solving for this :tan∠A  csc∠C = 3x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0here are the variables

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0tangent A= 7/sqrt 74 and csc C= sqrt74/5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0idk what you are saying

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Its tangent a subtracted from cosecant C and those are the values of them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What the bannana are you talking about?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Wait, I'm confused. So you have: \[\tan A  \csc C = 3x\] And: \begin{align} \tan A &= \frac{7}{\sqrt{74}}\\ \csc C &= \frac{\sqrt{74}}{5} \end{align} Right?

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0jonh—please be respectful.

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so you really have: \[\frac{7}{\sqrt{74}}  \frac{\sqrt{74}}{5} = 3x\]

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0First things first, I would do the subtraction on the left. Do you know how to do that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you subtract the square?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So, 3x = 39/(5*SQRT(74)) => x = 13/(5*SQRT(74))

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you use the values GT?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am kind of shaky on how to subtract with squares shadowfield

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1326987711543:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1326987783481:dw

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0You can make the denominators the same by multiplying each fraction by the other fraction's denominator: \[\] \begin{align} \frac{7}{\sqrt{74}} & \frac{\sqrt{74}}{5}\\ \frac{5}{5}\frac{7}{\sqrt{74}} & \frac{\sqrt{74}}{\sqrt{74}}\frac{\sqrt{74}}{5}\\ \frac{35}{5\sqrt{74}} & \frac{74}{5\sqrt{74}}\\ \end{align} So you get: \[\frac{35  74}{5\sqrt{74}}\] GT has the rest of the work :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that the simplified answer? Because I don't see it on my answer choices?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1326988065164:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There are other ways to write it. What are the choices?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.074/15 , 75sqrt 74/5, 7sqrt74/15 or 74/21

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then, the ratios you gave for tan and csc must be wrong. Where did you get those from?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1326988372290:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I first had to find the missing side then use the ratios

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What is A and B and C?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, before I say that I found C by using the pythagorean therom and got sqrt 74?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I understand and that is right. BTW  from the picture, I can already tell your Tan(a) is wrong. There is no hypotenuse involved in the tangent ratio.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok wait... let me post the letters

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1326988584560:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry for the messiness lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Good. Now, we can do it right. Tan A = BC/AB (opposite / adjacent) = 7/5 Csc C = AC/AB (hypotenuse / opposite) = SQRT(74)/5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now subtract and you will get the right answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1326988606286:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That is equal to 3x. Now, x will be equal to 1/3 of that value.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dw:1326988707325:dw

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So you multiplied both sides by 5?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0WOOHOOO!! Thank you so much I got a 100!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Great. Hope you also now can solve such problems with ease!
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