A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
tan∠A  csc∠C = 3x
anonymous
 4 years ago
tan∠A  csc∠C = 3x

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How do you solve this?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0At some point I got 3x sqrt74/5= 7/sqrt 74

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am confused because you have 3 variables, A, C and x. what are you trying to solve?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am solving for this :tan∠A  csc∠C = 3x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0here are the variables

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0tangent A= 7/sqrt 74 and csc C= sqrt74/5

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0idk what you are saying

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Its tangent a subtracted from cosecant C and those are the values of them

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What the bannana are you talking about?

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.0Wait, I'm confused. So you have: \[\tan A  \csc C = 3x\] And: \begin{align} \tan A &= \frac{7}{\sqrt{74}}\\ \csc C &= \frac{\sqrt{74}}{5} \end{align} Right?

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.0jonh—please be respectful.

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, so you really have: \[\frac{7}{\sqrt{74}}  \frac{\sqrt{74}}{5} = 3x\]

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.0First things first, I would do the subtraction on the left. Do you know how to do that?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you subtract the square?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So, 3x = 39/(5*SQRT(74)) => x = 13/(5*SQRT(74))

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0did you use the values GT?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am kind of shaky on how to subtract with squares shadowfield

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1326987711543:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1326987783481:dw

shadowfiend
 4 years ago
Best ResponseYou've already chosen the best response.0You can make the denominators the same by multiplying each fraction by the other fraction's denominator: \[\] \begin{align} \frac{7}{\sqrt{74}} & \frac{\sqrt{74}}{5}\\ \frac{5}{5}\frac{7}{\sqrt{74}} & \frac{\sqrt{74}}{\sqrt{74}}\frac{\sqrt{74}}{5}\\ \frac{35}{5\sqrt{74}} & \frac{74}{5\sqrt{74}}\\ \end{align} So you get: \[\frac{35  74}{5\sqrt{74}}\] GT has the rest of the work :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that the simplified answer? Because I don't see it on my answer choices?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1326988065164:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There are other ways to write it. What are the choices?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.074/15 , 75sqrt 74/5, 7sqrt74/15 or 74/21

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Then, the ratios you gave for tan and csc must be wrong. Where did you get those from?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1326988372290:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I first had to find the missing side then use the ratios

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What is A and B and C?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Well, before I say that I found C by using the pythagorean therom and got sqrt 74?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I understand and that is right. BTW  from the picture, I can already tell your Tan(a) is wrong. There is no hypotenuse involved in the tangent ratio.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok wait... let me post the letters

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1326988584560:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry for the messiness lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Good. Now, we can do it right. Tan A = BC/AB (opposite / adjacent) = 7/5 Csc C = AC/AB (hypotenuse / opposite) = SQRT(74)/5

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now subtract and you will get the right answer.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1326988606286:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That is equal to 3x. Now, x will be equal to 1/3 of that value.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1326988707325:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So you multiplied both sides by 5?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0WOOHOOO!! Thank you so much I got a 100!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Great. Hope you also now can solve such problems with ease!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.