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anonymous

  • 5 years ago

Consider the following electric field: What is the magnitude and sign of the coulomb force between the two charges. Assume the left test charge has a magnitude of 1.0 c and they are 1m apart

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  1. anonymous
    • 5 years ago
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  2. anonymous
    • 5 years ago
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    I would assume it still goes kQ1Q2/m^2? , but I don't know how to determine the charge of the second one

  3. JamesJ
    • 5 years ago
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    If you're not given options, I would guess the magnitude second charge. It's clear the situation isn't symmetric because the field lines aren't symmetric. If I had to guess, I'd say the right charge was 1/2 the left one.

  4. anonymous
    • 5 years ago
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    So if we assumed it was half as strong the equation for the magnitude would be \[(9*(10^9) * 1 * .5) / 1^2\]

  5. anonymous
    • 5 years ago
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    and the sign I guess would be positive?

  6. JamesJ
    • 5 years ago
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    Sign convention is a tricky thing but physically the force acting on one charge should be pointing towards the other, that's the germane thing.

  7. JamesJ
    • 5 years ago
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    (I see now though that the question asks explicitly about sign. I'm not sure exactly what convention you're using, but I'm guessing in this case you want it almost certainly to be positive. Check your class/lecture notes.)

  8. unicorn
    • 5 years ago
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    electric field lines originate from positive charge and from infinity and terminate at negative charge or infinite and secondly magnitude of charge is directly proportional to the no of lines originating from charge. . now in yours Que A is + and B is negative and if B is 1C then A will be 18 C and so on and force between them can be calculated using Coulomb law

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