A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
how can we estimate the gravitational force of attraction between two people sitting side by side on a bench? How does this force compare with gravitational force exerted on each of them by the earth(weight)?
anonymous
 4 years ago
how can we estimate the gravitational force of attraction between two people sitting side by side on a bench? How does this force compare with gravitational force exerted on each of them by the earth(weight)?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I suppose you could "estimate" it by taking the product of their two masses, and about 7*10^5...? \[\Large \begin{array}{l} g = G\frac{{{m_1}{m_2}}}{{{r^2}}}\\ = 6.673 \times {10^{  11}} \cdot \frac{{{m_1}{m_2}}}{{{r^2}}}\\ {m_1} = {m_2} = 60{\rm{kg}}\\ r = 0.01{\rm{m}}\\ {r^2} = 0.000001{\rm{m}}\\ 6.673 \times {10^{  11}} \times \frac{{3600}}{{0.000001}}\\ = 6.673 \times {10^{  11}} \times 3600000000 = 0.240228\\ 3600 \cdot 7 \times {10^{  5}} = 0.252 \end{array}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But to be honest I think this is a pretty askew question =)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This is a common question in "physics 101". Teachers like to get across the idea that gravitational forces exist between all things having mass, albeit these forces are usually negligible.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh yes, I was referring to the asking to "estimate" the attraction. Unless by "estimate" they mean actually work it out to the best of your abilities, since this is in itself an estimation at best.

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.2(One small thing. In the formula fsm has written above, he starts with g = .... It should be the force, F = .... )

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answers i have to it is 10^6N is there anyway to find that out?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You'll need to set the radius and mass of the two people. This data isn't given, so a precise answer cannot be found.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but how do we estimate this value?

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.2But the distance used in the calculation above isn't perhaps the best approximation. The distance between their center of masses is likely to be closer to 1 m than 0.01 m.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and the weight is greater by a factor of 10^9 ? what value of masses should we estimate? 5080kg?

JamesJ
 4 years ago
Best ResponseYou've already chosen the best response.2Sure. 70 kg is as good as any other point estimate. As has been pointed out above, the purpose of the exercise isn't the precise number, but showing it is so much less than the gravitational force of the earth.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Haha yeah, everything about my example was a bit awful. Apologies.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.