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anonymous
 5 years ago
What is the equation of the graph below?
a. y = –1(x – 4)2 + 1
b. y = –1(x + 1)2 + 4
c. y = 1(x + 1)2 – 4
d. y = 1(x + 4)2 – 1
anonymous
 5 years ago
What is the equation of the graph below? a. y = –1(x – 4)2 + 1 b. y = –1(x + 1)2 + 4 c. y = 1(x + 1)2 – 4 d. y = 1(x + 4)2 – 1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I thinkits b, am i right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0vertex is \[(1,4)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can see it right? the vertex i mean

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0b/c u have to flip 1 to 1 an then 4 stays

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because of the following \[(x+1)^2\geq 0\] for any x, because it is a square. therefore the very least it can be is 0 and it is zero if x = 1 if x =  1 then \[(x+1)^2=(1+1)^20\] and \[(x+1)^24=(1+1)^2=04=4\]
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