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anonymous

  • 5 years ago

Number 17

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  1. anonymous
    • 5 years ago
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  2. Hero
    • 5 years ago
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    To solve this, you simply set y = 0, and solve for x. The right-most x will be a bigger value than the leftmost x

  3. anonymous
    • 5 years ago
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    ok i got to x^2-6x+6 ...where do i got from here?

  4. Hero
    • 5 years ago
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    x^2 - 6x + 6 = 0

  5. anonymous
    • 5 years ago
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    i plugged zero in for y, foiled on one side, and subtracted 3

  6. Hero
    • 5 years ago
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    Did you figure it out yet?

  7. anonymous
    • 5 years ago
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    nope, just got the wrong answer

  8. anonymous
    • 5 years ago
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    o wait, do i use the quadratic formula?

  9. Hero
    • 5 years ago
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    Try (4.732, 0)

  10. anonymous
    • 5 years ago
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    its just 4.732 because its only asking for the x coordinate

  11. Hero
    • 5 years ago
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    I see

  12. anonymous
    • 5 years ago
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    so how did u get that #?

  13. Hero
    • 5 years ago
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    I approximated \[x = \sqrt{3} + 3\]

  14. anonymous
    • 5 years ago
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    how did u get that from x^2-6x+6=0?

  15. Hero
    • 5 years ago
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    Well, to be honest, I back tracked to when you had 3 = (x-3)^2 Instead of putting everything on one side, I simply square rooted both sides to get: sqrt{3} = x - 3 Then I added 3 to both sides. Why? Because we wanted to solve for x.

  16. anonymous
    • 5 years ago
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    Ok I see

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spraguer (Moderator)
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