## anonymous 4 years ago Number 17

1. anonymous

2. Hero

To solve this, you simply set y = 0, and solve for x. The right-most x will be a bigger value than the leftmost x

3. anonymous

ok i got to x^2-6x+6 ...where do i got from here?

4. Hero

x^2 - 6x + 6 = 0

5. anonymous

i plugged zero in for y, foiled on one side, and subtracted 3

6. Hero

Did you figure it out yet?

7. anonymous

nope, just got the wrong answer

8. anonymous

o wait, do i use the quadratic formula?

9. Hero

Try (4.732, 0)

10. anonymous

its just 4.732 because its only asking for the x coordinate

11. Hero

I see

12. anonymous

so how did u get that #?

13. Hero

I approximated $x = \sqrt{3} + 3$

14. anonymous

how did u get that from x^2-6x+6=0?

15. Hero

Well, to be honest, I back tracked to when you had 3 = (x-3)^2 Instead of putting everything on one side, I simply square rooted both sides to get: sqrt{3} = x - 3 Then I added 3 to both sides. Why? Because we wanted to solve for x.

16. anonymous

Ok I see